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PiJI��' ��I.EC'I'IOI�T PRO�EI�LTi�i� <br /> 1�a ��$�y'1�"Algl� �3�lI7Cl�➢ C����flt�l: <br /> ,. f�. G]C��7fl��7 �1S�g1�l.�tflOY� <br /> 1. Minimum required discharge is 10 gpin <br /> 2. 1Vlaximum suggested discharge is 45 gpm. For other <br /> estaUlishments at least 10%greatei- than the water supply rate, <br /> Uut no faster than the rate at which eff�uent will Ilow out of the <br /> disri-iUution device. ' �� i <br /> lE�. �Yc��.�r�Lfl�'� ��St��'I����1�Y� <br /> See ��ressure distYibutiort work sheet <br /> ��r��u l-� �� � ����cte� �u��a� c����it�: � I �p��a� <br /> 1e I�'�$c...Pfl"Y"&�1E3�_�7Y..fli1�� ����� �'��LflA��'IIll��B�at�o <br /> 1�. Elevation difference between pLunp and point of discharge? soil treatment system <br /> _ � __feet <br /> &point of discharge <br /> aop�D�?°a.�' Jc7 a <br /> 1�.Special head requirement? (See Figicre at right- Special Head Reqi�irenients) total pipe <br /> / �, length <br /> _ S feet � r � 2A.elevation <br /> ' inlet `_ difference <br /> �. Calculate Friction loss pipe �.`d <br /> �; ------- -- -� <br /> l. Select pipe diameter ��� in " ` � <br /> ,. <br /> --�---�---��-�---- - � <br /> --------------------------- ------ <br /> '?. Enter Figicre E-9 wit11 gpm (lA or B) end pipe diameter (C1). , <br /> Read friction]oss uz feetper 100 feet from Fig-tti-e �-9 Special Head Requirements <br /> Friction Loss = I_�s ft/100ft of pipe Gravity Distribution 0 ft <br /> �. Determine total pipe length h-om purnp discharge to soil tre�tment Pressure Distribution 5 ft <br /> discharge poult. Estimate by adding 25 percenf to pipe lengt-h for <br /> fittulg loss. Total pipe length tiines 125 - equivalent pipe le:ngth � <br /> E-;9: Friction Loss in Plas4ic Pip� <br /> `f� feet x 1.25 = .S� feet <br /> Per 1�0 f€�et <br /> 4_ Calculate total hiction loss by multiplying frictior�loss (C2) nomina9 <br /> in ft/100 ft by the equivalent pip� length (C3) and divide by 100. pipe diom�ter <br /> _ /.C,o ft/100ft x �� =100 - � ft (iow rate 1.5" �" 3" <br /> - p,t�n <br /> �. Total head required is Ehe sum of ele��ation difference (A),special 20; 2•47 0.73 0.11 <br /> head requirements (B), and total friciion lc�ss (C�) 25; 3J3 1.11 O.lb <br /> �ft+_ .� It+_�__ft- 30 5.23 1.55 0.23 <br /> ,�,���� ����� /� ¢��� 35 6.9c5 2.06 0.30 <br /> _ _ _ _ 40 8.91 2.64 0.39 <br /> 45 11.07 3.28 0.48 <br /> �� ��R��� ������g��� - 50 13.46 3.99 0.58 <br /> 55 4.76 0.70 <br /> 1�puinp must Ue selected to deliver at least_ �/ �pm �p 5.60 0.82 <br /> (lA or B) wilh at least �� f�et of total head (2D) 65 6.48 0.95 <br /> S 70 � 7.44 1.09 <br /> I hereby c_ertify that I have completed dzis work in accordance with applicable ordinances, rules and laws. <br /> ��_ �"'� � � ��""� (signature) �� � (license#) I 2 -1�-'(7� (date) <br />