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PUMP SELECTION PROCEDURE <br /> A. Determine pump capacity: <br /> Gravity Distribution <br /> 1. Minunum suggested is 20 gpm <br /> 2. Maximum suggested is 45 gpm <br /> Pressure Distibution <br /> 3. a. Select number of perforated laterals Perforation Discharges in GPM <br /> b. Select perforation spacing= feet. Head Perforation diameter <br /> c. Subtract 2 ft. from the rock layer length. feec inches <br /> R«���yer�engw'2 ft.= feet. �/32 i/4 <br /> d. Determine the number of spaces between perforations. 1.oa 0.56 0.�4 <br /> Length perf.spacing= ft.+ ft. = spaces 1.5 0.69 0.90 <br /> e. spaces+1 = perforations/lateral 2.ob o.8o i.o4 <br /> f. Multiply perforations per lateral by number of laterals to a Use 1.0 foot single homes. <br /> b Use 2.0 feet for anything else. <br /> get total number of perforations. �r x ��S � = perforations. <br /> g' � X RPm � - BPm. <br /> SELECTED PUMP CAPACITY ��S 1 gpm <br /> Soil treatment system <br /> B.Determine head requirements: <br /> 1. Elevation difference between pump and point of discharge. °�°��°��°� <br /> _�feet Total pipe length <br /> 2. If pumping to a pressure distribution system,five feet for pressure <br /> required at manifold if gravity system,zero. <br /> � feet �e� Elevabon Difference <br /> pipe <br /> 3. Friction loss . ______ <br /> a. Enter friction loss table with gpm and pipe diameter. .�..�-....-..... � . <br /> ------------------------------------- <br /> Read friction loss in feet per 100 feet from table(F-14). <br /> F.L. _ �.. (.�I ft./100 tt of pipe <br /> b. Determine total pipe length from pump to discharge Friction Loss in Plastic Pipe <br /> point. Estunate by adding 25 percent to pipe length for fitting Nominal <br /> loss,or use a fitting loss chart(F-15 feet). pipe dia. <br /> Equivalent pipe length-1.25 times pipe length= Flow Rate <br /> II D x 1.25=_ 1 3 ff feet �m 1.5" 2" 3" <br /> c. Calculate total friction loss by mulriplying <br /> friction loss in ft/100 ft by equivalent pipe length. 20 2.47 0.73 0.11 <br /> Total friction loss= _a•(o�l x J 3£s +100=�feet � 3.73 1.11 0.16 <br /> 4. Total head required is the sum of elevation difference, 30 5.23 1.55 0.23 <br /> 35 6.96 2.06 0.30 <br /> special head requirements,and total friction loss. 40 8.91 2.64 0.39 <br /> 45 11.07 3.28 0.48 <br /> �+_�+�-� 50 13.46 3.99 0.58 <br /> (1) (2) (3c) 55 4.76 0.70 <br /> 60 5.60 0.82 <br /> 65 6.48 0.95 <br /> TOTAL HEAD �Z feet 7� 7.44 1.09 <br /> C. Pump selection <br /> 1. A pump must be selected to deliver at least <br /> �g_gpm (Step A) with at least ..�_feet of total head (Step B). <br /> � <br />