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1005 Heritage Lane - 10-117-23-12-0005
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Last modified
8/22/2023 3:18:39 PM
Creation date
1/24/2017 10:49:23 AM
Metadata
Fields
Template:
x Address Old
House Number
1005
Street Name
Heritage
Street Type
Lane
Address
1005 Heritage Lane
Document Type
Septic
PIN
1011723120005
Supplemental fields
ProcessedPID
Updated
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� � MOUND DESIGN WORKSHEET <br /> � (For Flows up to 1200 gpd) <br /> A. FLOW Estimated Sewage Flows in Gallons per day <br /> d <br /> Estimated 6�r� gpd N�� �� �u �►yam � <br /> or measured x 1.5 = gpd. °` <br /> 2 30o ns iso � <br /> B. SEPTIC TANK LIQUID VOLUMES 4 �ao 330s Zs�. °`,'� <br /> s �so aso z9a. ��"� <br /> �S U(� gallons 6 900 525 332 T�� <br /> 7 1050 b00 370 11 a <br /> 8 1200 675 408. W <br /> C. SOILS (refer to site evaluation) `�`n""S <br /> 1. Depth to restricting layer = �inches � feet �`p"`�"'`�'�°`"'`���°g°"°'�� <br /> 2. Depth of percolation tests = �a- lIl�eS Number of Minimum Liquid Liquid capacity with <br /> Bedrooms Capacity garbage disposal <br /> 3. Texture Gar�M Percolation rate �,v mpi <br /> 4. Land slope �- � % Z3 0�as ioo°o isoo <br /> 5 or 6 1500 2250 <br /> 7,8 or 9 2000 3000 <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 = <br /> bo� gpd x 0.83 sq. ft./gpd = vv sq, ft. <br /> 2. Select width of rock layer (max 10' if<120 mpi max 5') _ /c� ft. <br /> 3. Length of rock layer = area +width = a6:-� a�- � �6-a. a <br /> 9.'�����a�.4�.,a 4�'Cf,4� � � y, Y� , <br /> 6 R �e 4'u 6�''� R y .o'. <br /> -I- W,w 4R 9�}�.�L7�}�44A-O d. <br /> s�v sq. ft. �o ft. _�ft. � <br /> :Qa �Q�O�aR ti 6'�a 6'�6 a Q�o�. P . . � <br /> �.�r � S>'G�P u0 C� �D�:. .,.. .,. _ :. _ .. . . . . <br /> WI�Lll�_�L -tl . "._..y;.: ,_G..p`P D ;:D r.�, o-�. .a:p -��� <br /> <120mpi <10' Length sz�� ft <br /> E. ROCK VOLUME >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; s�� sq. ft. x i,o s <br /> �, - sa s cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> sa�s cu. ft. +27= i 9. s cu. yd. � <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; �g•� cu. yd. x 1.4 <br /> ton/cu. yd. =a 7. 3 tons. <br /> F. ABSORPTION WIDTH Absorptlon Width Siziug 1Lble <br /> 1. Percolation rate in top 12 inches of soil is 5 mpi P+ercotuirn[t�r�in Gallons RazioofAhsaption <br /> Texture LD/�M rdinutes pu Inch Soil Texture per day per width to Rock <br /> (MPI) squarc foot Laycr Width <br /> . Faster than 0.1 Couse Sand 1.20 I.00 <br /> 0.1 to S Sand 1.20 I.00 <br /> 2. Select allowable soil loading rate from table; o.��o s Fine Sand o.�o z.00 <br /> -!� d/ft2 6w30 S'°d� o:�o z:� <br /> � s�co as s�ic�,o�ro oso z.ao <br /> 46 W 60 Clay Loam 0.45 2.67 <br /> 60 to 120 Qay 0.24 5.00 <br /> 3. Calculate adsorption width ratio by dividing rock layer s�oW����,�zo c,.Y o.zo b.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/ftz+�_gpd/ft� = a � <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> �.. X io �= av �{ <br />
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