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2010-00363 - septic mound system
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2010-00363 - septic mound system
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Last modified
8/22/2023 5:15:22 PM
Creation date
1/12/2017 3:54:40 PM
Metadata
Fields
Template:
x Address Old
House Number
3355
Street Name
Graham Hill
Street Type
Road
Address
3355 Graham Hill Rd
Document Type
Septic
PIN
0511723110008
Supplemental fields
ProcessedPID
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Vurvcxxirr oc�tn�srsmn <br /> � Pressure Distribution Design _ � - <br /> ��, � <br /> Minnesota Pollution Worksheet `�"' <br /> Control Agency ' "° ` �" <br /> 1. Select Number o Per orated Laterats : � Geote�ile <br /> f f �pOpppOpg�p0��9��Oq�� Minimum D�pO�° o0_'�q�D�pO <br /> oc /:' perforations spaced 3'apart�c� Z"of rak�o o�o�o <br /> (2-3 foot spacing) o�o�oo <br /> 2. Setect Perforation 5pocing: 3.0 ft o�o o. t1" �_ <br /> o`��0'�30 0��e o• [�d�.ri�d�o�oo�o'��{('o�p o00 <br /> Note:Must use 2 feet for media filters °"Do� �"`�� 9•of rak�D R�Dk�O�D�Do�o c�oo <br /> a�a� ��a�a , ��a�������� <br /> 3. Select Perforation Diameter Size 7132 inch Perfo2ti0n Sili�:'/e'Lo'!�" <br /> Per(wation acin :2'to 3' <br /> 4. Length of Laterels =Media Bed Length-2 Feet. Perforation can not be ctoser then 1 foot from edge. <br /> 63 - 2ft = 61 ft <br /> 5- Determine the Number of Perforation Spaces. Divide the Length of Laterals (Line 4)by the Perforation Spacing (Line 2)and <br /> round down to the nearest whole number. <br /> Number of Perforation Spaces = 61 ft .- �ft = 20 Spaces <br /> b. Number of Perforations per Lateral is equal to 1.0 plus the Number of Perforotion Spaces (Line 5). <br /> Perforntions Per Lateral = 20 Spaces + 1 = 2� Perfs. Per Lateral <br /> Check Tub(e!to ensure that the number of perforations per lateral guarantees less than o 10%discharge variation. <br /> 7• Total Number of Perforations equals the Number of Perforotions per l.atera( (Line 6)muttiptied by the Number of <br /> Perforated Latera(s (Line 1). <br /> 21 Perf. Per Lateral X �Number of Pert. Laterals = 63 Total Number of Perf. <br /> 8. Calculate the Squore Feet per Perforation. Recommended v4lue is 4-10 ftZ per perforation. Tabk III <br /> Does nat apply to At-Grades aer�oration oisctwrge(GPM) <br /> Bed Area = Bed Width(ft)X Bed Length(ft) Pertoration Diameter <br /> Flead(ft) <br /> i�e ��„ ��71 ��, <br /> 10 ft x 63 ft = 630 ftZ �.o• o.�s o.�� o.se o.�4 <br /> Z,p" 0.26 0.59 0.80 1.04 <br /> Square Foot per Perforation =Bed AreQ divided by the Tota!Number of Perforations (Line 7). 5• °.4� o.9a �.ze 1.65 <br /> a:Use 1.0 for dwetlings iainq 1!4 inch or 3/16 inch <br /> hdes. <br /> 630 ftZ = 63 pertorations = 10.00 ftz�perforations b:Use 2.0 for dwellings using 1/8 inch hdes;a,r� <br /> other establishments usinq 1/4 inch or 3/16 inch <br /> hdes. <br /> 9. Setect Minimum Average Head: 1.0 ft c:Use 5.o for oU�er ertaWishments ising��8 irKh <br /> perforations a�d media filters. <br /> 10. Select Perforation Discharge (GPM)based on Table I11: 0.56 GPM per Perforation <br /> 11• Determine required F(ow Rate by muttiplying the Tota!Number of Perforations (Line 7)by the Perforotion Dischorge (Line 10). <br /> 63 Perforations x 0.56 GPM per Perforation = 36 GPM <br /> 12. Setect Type of Manifold Connectfon (End or Center): �end ❑Center <br />
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