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OSTP Pressure Distribution <br /> UNIVERSITY � `� <br /> Minnesota Pollution Design Worksheet OF MINNESOTA � <br /> Control Agency �-�\`" <br /> 1. Select Number of Perforated Laterals in system/zone: � Geotextile <br /> �6Cgp9p�0'q���p��6�p�0�0'qr°pOC Minimum�q�p0� 0'�(��D <br /> (2 feet is minimum and 3 feet is maximum spacing) o�'/`perforations zparnd 3`apart��q 2"of rock��� ti 0��°p��p0 <br /> 2. Select Perforation Spacing: 3.0 ft o��od����n o� ����n�,o���a�o'�- <br /> poO�poCy�o aDodaJo�?�Do�p.�r 9"of rock�DoGV0o0uDo'JsJoOeDo�O�"q�0 <br /> 3. Setect Perforotion Diameter Size 7/32 inch ������ � �� ��� �� �� � <br /> o"�o° o�co�.`,noo°�oo' o; L�b"�'o°��oo'�oo�o oo°'��o° �`-30" <br /> Vertorauon sizing:'h"to 41' <br /> Perioration s acin :7 to 3' <br /> 4. Length of Loterols =Media Bed Length -2 Feet. Perforation cQn not be doser then i foot from edge. <br /> 63 - 2ft = 61 ft <br /> 5• Determine the Number of Perforation Spaces. Divide the Length of Latero(s (Line 4)by the Perforation Spacing (Line 2)and <br /> round down to the nearest whole number. <br /> Number of Perforation Spoces = 61 ft .- �ft = 20 Spaces <br /> 6. Number of Perforntrons per Latero( is equat to 1.0 plus the Number of Perforation Spntes (Line 5). <br /> Perforations Per taterol = 20 Spaces + 1 = 21 Perfs. Per Lateral <br /> Check Toble 1 to verify the number of perforations per(aterol guarontees(ess ttwn a 10%dischorge variation. The va(ue is double if <br /> the a center manifold is used. <br /> 7• Total Number of Perforations equals the Number of Perjorations per Lateral (Line 6)multiplied by the Number of <br /> Perforated Laterals (Line 1). <br /> 21 Perf. Per Lateral X �Number of Perf. Laterals = 63 Total Number of Perf. <br /> 8. Calculate the Square Feet per Perforotion. Recommended va(ue is 4-10 ft Z per perforation. ' P�,,,,,n,,,axn„s�(GPM) <br /> Does not appty to At-Grades P�.ro�a�ti«�o;amer�. <br /> 'neaa lRl ,�` � ,�. _ ,/. <br /> Bed Area = Bed Width (ft)X Bed Length (ft) .- <br /> �. 1.0' 0.18 0.41 O.S6 0.76 <br /> 10 ft x 63 ft = 630 ftZ +_5 a.== o.s, 0.69 a.9 <br /> 2.0° 0.26 0.59 0.80 1.04 <br /> � 2.5 0.29 0.65 0.89 1.17 <br /> Squore Foot per Perforotion =Bed Area divided by the Total Number of Perforations (Line 7). '.o °.'z °.'2 °.°e ,.2° <br /> 4.0 0.J7 0.83 1.13 1.47 <br /> � SA` O.4f 0.93 7.26 1.65 <br /> 630 ftZ - 63 (��OfdtlOfl$ C �0.� ftZ/perforations ' ,f�, ��4'^�narc13ii6inchperforatianon <br /> Cwellings <br /> 9. Select Minimum Averoge Head: 1.0 ft ��8��ch petforatlons on dwAlirms and far <br /> z(pp( OtRP/P.tdbli5lfTQ�IS <br /> t/4 inch ard 3/tn inch pefwatiom on M57S <br /> ' S f�[ //8�nch perforations on MSTS <br /> ' __ _.. .._ .__ _ .. _...._. __." <br /> 10. Select Perforation Discharge (GPM)based on Table III: 0.56 GPM per Perforation <br /> 11• Determine required Flow Rate by multiplying the Tota(Number of Perforations (Line 7)by the Perforation Discharge (Line 10). <br /> 63 Perforations X 0.56 GPM per Perforation = 36 GPM <br /> 12. Select Type of Manifold Connection (End or Center): � End ❑ center <br />