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Pressure Distribution Design �'m�u=A�"` <br /> MlnnesotaPollution Worksheet � _ �� ��- - <br /> Controi Agency . - _ : �����,� <br /> � <br /> 7. Select Number oj Perforated LaterQis(1-3 foot spacing)• r 3� � �-a„� M� � <br /> L- 'v- �ssP�� z•otrodc <br /> 2• Select Perforetion Spocing(<9 ft Z/perforation): 3.0 ft ' <br /> iz• <br /> Note:Must use 2 feet for media�r[ters 9.�� �� �t'a� <br /> 3. Select Perforation Diameter 7/32 inch � <br /> Perforation sizing:'/�'to'/.' <br /> Perioration ' 2'to 3' <br /> 4 Length of Laterats =Media Bed Length-2 Feet Perforation cnn not be closer then 1 foot from edge. <br /> 63 - 2ft = 61 ft <br /> 5- Determine the Number of Perjoration Spaces. Divide the Length oj Lvterals (Line 4)by the Perforotion Spnci►►g (Line 2)and <br /> round down to the nearest whote number. <br /> Number of Perforation Spaces = 61 ft : � 3 �ft = 20 Spaces <br /> t_—._ <br /> 6. Number of Perforotions per Loterol is equat to 1.0 plus the Number of Perforehon Spoces (Vne 5). <br /> Perforotions Per Lateral = 20 Spaces + � = 2� <br /> Check Table l to ensure that the number of perforutfons pe�(ateral guarantees/ess thun o 1pyK disdwrge variotion. <br /> Table 1 Ma�dmum Number of Perfiorations Per Lateral to Ca�a�-antee<10%Discharge Yariation <br /> �/4 ktch Noles '/aa tnch Holes <br /> Perforatan Pipe Diameter(Inches) Per�oraition Pipe Diameter(Inches) <br /> �a�8��) 1 114 13�e 2 3 Spaong(Feet) 1 1Y. 134 2 3 <br /> 2 10 13 18 30 60 2 11 i6 21 34 68 <br /> 2� 8 12 16 28 54 234 10 14 20 32 64 <br /> 3 8 1Z 16 25 52 3 9 14 19 3p 6p <br /> '��s Inch Holes '�e ind�Hotes <br /> Per(oration Pipe Diameter(Inches) Perfora�on Phpe Diameter(inches) <br /> `�Pa��S�F�) 1 1'6i 134 2 3 Spacing(Feet) 1 134 134 2 3 <br /> Z 12 18 26 46 E7 2 21 33 M 74 449 <br /> 2� 12 17 24 40 80 2S4 20 30 41 69 135 <br /> 3 12 16 22 37 T5 3 2p 29 38 64 128 <br /> �• Tota!Number of Perforations equals the Number of Perforations per Lateral (Line 6)muttiplied by the Number of <br /> Perforoted Lnterols (Line 1). <br /> 21 Perf. Per Lateral X ��Number of Perf. Laterats = 63 Total Number of Perf. <br /> tatculate the Sqaere Feet per Perforotion <br /> 8. Bed Area = Bed Width(ft)X Bed Length(ft) <br /> 10 ft x 63 ft = 630 ftz <br /> 9. Square Foot per Perforotion =Bed Area (Line 8)divided by the Totai Number of Perforntions (Line 7). <br /> 630 ftz .- 63 perforations = 10.00 ftz/perforations <br /> Recommended value is 410 ft2 per perforation. Does not appty to At-Grades <br /> CONTINUED ON NEXT PAGE <br />