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OSTP Pressure Distribution w <br /> UNIVERSITY `�'rv'• <br /> Minnesota Poilutbn Desi�n Worksheet OF MINNESOTA � ° � <br /> Control A enc -�":;�� <br /> Project ID: v 11.09.22 <br /> 1. Select Number of Perforated Laterols in rystem/zone: � _______ <br /> .,,�.,�,.,.k..�.,�.,, <br /> (2 feet is minimum and 3 feet is moximum spacfng) '° __ <br /> �� -� <br /> 2. Select Perforation Spactng: 3.0 ft 'Z'` . � ,1 s�',•`o"" _ - <br /> � <br /> % Miitimum <br /> '/."Der7o�:�t�onx sP�ced 4'ap��t 1'?'nf�ork �~ t]" <br /> 3. Select Perforation Diameter Size 7/32 in _ _ <br /> F'of�ock <br /> 4. length of Loterals =Media Bed Length-2 Feet. °e"°.°'�°^s��'^�" '�°'�' ��"°�°"°^sv,,�'^„,'��'• <br /> 50 - 2ft = 48 ft Perforotfon can not be closer then 1 foot from edge. <br /> 5• Determine the Number of Perforntion Spaces. Divide the Length of Leterols (Line 4)by the Perforation Spacing (Line 2)and <br /> round down to the nearest whole number. <br /> Number of Perforation Spaces = 48 ft .- �ft = 16 Spaces <br /> 6. Number of Perforations per Lnteral is equal to 1.0 plus the Number of Perforntion Spaces (Line 5). <br /> Perforations Per Lateral = 16 Spaces + 1 = 17 Perfs. Per Lateral <br /> Check table be(ow to vertfy the number of perforatiorrs per(vtera!guarontees less thvn a f0%dischQrge varfntion. The value is <br /> double if the a center manifold is used. <br /> Maximum Nixnber of PcKforatiau Pes Lateral to GuaraMee<t096 Diuharge Yariakion <br /> '4 fnc P orabans 7/321nct�Perforallons <br /> Pipe Di�meter ll�xhes) Perforation Spacing Pipe Diameter(Inches) <br /> Pe+foratwn Spacing(Feet1 i 1Y+ 11� 2 3 (feet) 1 1Y� 1w 2 3 <br /> 2 10 13 16 30 60 2 11 1b Z1 34 6a <br /> 3ti'� 8 12 16 28 54 2� 10 14 20 32 64 <br /> � 8 12 tb 25 51 3 9 14 19 34 60 <br /> 3;'161rxh Perforations 1!81rxh Perfarations <br /> Pipe Diameter Ilnchesl Perforation Sp�acirtig Pipe Dsameter Anthez) <br /> Perforatwn Spacmg IFeet) <br /> 1 1�G 11h 2 3 (Feetl 1 114 1ti, 2 3 <br /> 1 11 18 2b 46 87 2 11 33 44 74 1�9 <br /> Z�Z 12 17 24 40 80 2�`� 20 30 41 69 135 <br /> 3 12 16 22 37 15 3 20 29 3E 64 12a <br /> �• Total Number of Perforotions equats the Number of Perforations per Latera! (Line 6)multiplied by the Number of <br /> Perforated Laterals (Line 1). <br /> 17 Perf. Per Lateral X �Number of Perf. Laterals = 51 Total Number of Perf. <br /> _ _ _____ --___-- ___ _ <br /> 8. Calculate the Square Feet per Perforation. Recommended va(ue�s 4-10 ft Z per perforotion. ^"'°""°"D1x'"�F�o""� <br /> Does not appl y to At-Grades ,p,��r�, "�`�"'�'D1�`� <br /> •,, ,,,, °,,, �, <br /> Bed Area = Bed Width(ft)X Bed Length(ft) �.o- o.�e o.�+ o.ss o.�s <br /> 7.5 0.22 0.51 0.69 0.9 <br /> �� ft X �J� ft = rJ�� ftZ zc' o.0 oss o.ao �.os <br /> :.s o.xv o.ss o.ev �.+� <br /> �.o o.sa o.s2 o.v� �.v <br /> Square Foot per Perforation =Bed Area divided by the Total Number of Perforations (Line 7). •.o o.» 0.•1 ,.,� ,.•� <br /> 5. O.It 0.9� 1.26 t.i5 <br /> DwNHng with 1/le inch to t/t irch <br /> 500 ftZ • 51 pertorations = 9.8 ftZ/perforations '`°°` v�«a�� _ <br /> Owellimy vAN 7/8 Yxh pertontbrrs <br /> 3 feec Other r,[aDlh,hmencs nnd.v5T5 wi[�:/i6 <br /> 9. Select Mlnimum Average Head: 1.0 ft Incn io t/a ixh peAoracbra <br /> s r�ec aner euawnnmer�is a�a rnsts.ncn i re��n <br /> per/ofa[ioris <br /> 10. Select Perforation Discharge (GPM)based on Table III: 0.56 GPM per Perforation <br /> 11• petermine required F(ow Rate by multiplying the Total Number of Perforations (Line 7)by the Perforation Discharge (Line 10). <br />