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s�„�� Site B lot 1 block 1 Job#� <br /> TRL'ATMlNT <br /> PROORAM �. " <br /> University of Minnesota Mound Design Worksheet <br /> Greater than 1%Slopes <br /> a F�ow <br /> Estimat�d 750 gpd(see figure A-1) <br /> or measured x 1.5(safety factor)= 0 gpd <br /> B. SEPTIC TANK LIQUID VOLUMES <br /> Septic tank capacity 300o gallons(see figure C-1) <br /> Number of tankslcompartments 0 <br /> Effluent Filter (yes/no) yes <br /> C-1 Septic Tank Capacity in Galbns <br /> Number of Minimum Capacity with Capacity with <br /> Bedrooms Capacity Garb.Disp. Disp.and Lift <br /> 2 orless 750 1125 1500 <br /> 3 or4 1000 1500 2000 <br /> 5 or6 1500 2250 3000 <br /> 7,8 or 9 2000 3(�0 4000 <br /> C. SOILS(Site evaluation data) <br /> 1. Depth to restricting layer- 1.1 feet <br /> 2. Depth of percolation tests= 12 inches <br /> 3. Texture loam <br /> 4. Soil loading rate(see Figure D-33) 0.60 gpd/ftz <br /> Percolation rate 22 MPI <br /> 5. %Land Slope 4.0 % <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply average design flow(A)by 0.83 to obtain required area of rock layer:Item A x 0.83= <br /> 750 gpd x 0.83 ft2/gpd= 630 ftz <br /> 2. Determine rock layer width =0.83 ft`/gpd x Linear Loading Rate(LLR)(see LLR chart <br /> 0.83 ft2lgpd x 12.00 = 10.0 ft <br /> LLR Chart <br /> Perk Rate LLR <br /> <120 MPI <=12 <br /> >=120 MPI <=6 <br /> 3. Length of rock layer=area divided by width= <br /> 630.0 ft2 / 10.0 feet= 63.0 ft <br /> E. ROCK VOLUME <br /> 1. Multiply rock area by rock depth to get cubic feet of rock <br /> 630.0 X 1.0 ft= 630.0 ft' <br /> 2. Divide ft3 by 27 ft'lyd3 to get cubic yards <br /> 630.0 ft3 / 27 = 23.3 yd3 <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> 23.3 yd3 X 1.4 ton/yd3 = 32.7 tons <br /> . ,; r <br /> �s r' �-� <br /> � :;� � :>'�" <br /> �� ' :'� <br /> � <br /> f�� �� �,,� `�� <br /> Page 1 of 5 ��'� � L` <br />