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1998-010306 - new septic system
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1998-010306 - new septic system
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Last modified
8/22/2023 4:52:20 PM
Creation date
12/28/2016 1:59:22 PM
Metadata
Fields
Template:
x Address Old
House Number
140
Street Name
Golden View
Street Type
Drive
Address
140 Golden View Drive
Document Type
Septic
PIN
3311823430023
Supplemental fields
ProcessedPID
Updated
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� • ' , MOUND DESIGN WORKSHEET <br /> (Foi Flows up to 1200 gpd) <br /> A. �..OW Fstimuee sew�`e F1oM in c.u«�s per�.y(g� <br /> Estimated �S� gpd N�„� ,ry�l �ty�i� ryy�iu ry�rv <br /> or measured .- x 1.5 = - $pd• s�e'°°'"' <br /> 2 �oo us i eo � <br /> 3 �so �oo zia ,;; <br /> B. SEPTIC TANK LIQUID VOLUMES , boo »s u6 .�.� <br /> s �so �so �� <br /> f-1 a��i� � 1-l oo c7 gallons 6 90o sis »z � <br /> � toso 600 3�0 �m. <br /> d 1200 675 40A <br /> C. SOILS (refer to site evaluation) „ N�� ,,�� ��, <br /> ,, �, or �.... <br /> 1. Depth to restricting layer = a� oa�3�6 inches B�, � � <br /> 2. Depth of percolation tests = J a inches <br /> 3. Percolation rate 4�� mpi 2i«� �'o�oo i'.s o <br /> 4. Land slope 3 s«6 �soo �.�so <br /> % 7 a 3 7,000 �,000 <br /> wa 9 Sa+Rp C-6 (:l S) <br /> D. ROCK LAYER DIl�IINSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required azea of rock <br /> layer: A x 0.83 = <br /> ��'c� . gpd x 0.83 sq. ft./gpd = �aa._ sq. fta���=�uyp <br /> 2. Select width of rock layer (10 feet or less) _ /o ft. <br /> 3. Length of rock layer = azea+width = Rock Bed <br /> �_sq. ft. + �_ft. _�_ ft. ;.` ..,...,.�.. ..,., ..,:....�., <br /> r•} 1•t.1.I.�.}.r.f.}•r•1•r•r•�• <br /> � ♦ {.�.�.�.�.ti.�.ti.�.ti•ti•�.ti.�.� <br /> �.i.�.r•r•r.�•f•� r•r•r•r•r•r•�• �dth 510 ft. <br /> i.�.ti.�.�•ti.��•�•ti•�•�.ti•�•ti.ti•♦ <br /> ♦.f.f.r.f•f•r•�.r �•r•f•r•r•�•r• <br /> 1.\.ti.1.�.1.ti.�.ti•��1•�•1•ti•�•�.♦ <br /> •I•I.f•�•I•f•r•I•t t•t•t•t•I•1•t• <br /> E. ROCK VOLUME �- �"g�' -� <br /> 1. Multiply rock azea by rock depth to get cubic feet of rock; <br /> (,�sq. ft. x �,oS ft. _�.. cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft:/cu. yd. to get cubic yards; <br /> �►� �u. ft. .� �_�_�u. ya. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> �cu. yd. x 1.4 ton/cu. yd. _ � tons. <br /> F. ADSORPZION WIDTH �`"'� ' "�' a�,w,aw s�, Lbk <br /> �..o.,. �b.., <br /> 1. Percolation rate in top 12 inches of soil is 4.� mpi M�tl�� ���Texture �.� �,'� <br /> cm� �_ .:.�., <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 oarse Sand ��20 �•� <br /> � d�ft� O.l to5 Sand 1.20 1.00 <br /> r�1 $p 0.1 to 5 Fine Sand" 0.60 2.00 <br /> 6 to 15 ndy Loam 0.79 1 a2 <br /> 3. Calculate adso tion width ratio b dividin rock la er tb co 3o t.o�, o.bo 2.00 <br /> rp y g y 31 to 45 s��c t.�m oso z.ao <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; 61 �1 o cta��L°�' o2a �.00 <br /> 1.20 gPd/ft2l .�� gpd/ft� = a-l�� Slower than 120 Cla - - <br /> "SoU Fuvins 507G ar mae d firK a vcy fine sand <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> a.�� x�ft = ae,� ft <br />
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