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� OSTP Pressure Distribution <br /> UNIVERSITY <br /> Minnesota Pollution DesiQ n W�rk$heet � <br /> Control Agency S OF 1�/jINNESOTA -,�.�,;`�._ <br /> 1. Select Number of Perforated tatera(s in systemlzone: �3 � Geotextile + <br /> V��D�.OiD�DA��,aD��D�,��OvDo� Mi�imum�qppa� 0�g�p <br /> (2 feet is minimum and 3 feet is mo�c i m u m s p o c i n g) o��� Perfora!ions spaced 3'apart c�or; 2'of rock�o o��a <br /> 2. Select Perforation Spacins: 3.0 ft �a�,a>�� � ' oc���a�o�o � a_ 7z" D <br /> o°�.�onoo"�o"�"-�o'�� L�':-EYc�=�do'�o'�o"�'�.�o" d <br /> D�;7iD�C�D��•r-�D"•`>�^p�P�p90s � � C ��d ��6�5 <br /> "�"bo'�oo�co°�o';�Oo^G�'-"o b� 9"ofrockbo�Do�Oa�Do-�q�Do o�bc�aD�o <br /> � � �'o"�o�Gpo` �o�o�o'"� �p <br /> 3. Select Perforation Diameter Size 1/4 inch <br /> Perforacion sinng:'k"to Y." <br /> Perforation s uin :2'to 3' <br /> 4. Length of Latera(s =Media Bed Length-2 Feet. Perforation can not be doser then 1 foot from edge. v 11.05.31 <br /> 50 - 2ft = 48 ft <br /> 5• Determine the Number of Perforation Spaces. Divide the Length of Loterats (Line 4)by the Perforotion Spocing (Line 2)and <br /> round down to the nearest whole number. <br /> Number of Perforotion Spaces = 48 ft - � 3 �ft = 16 Spaces <br /> 6. Number of Perforations per LQtera( is equal to 1.0 plus the Number of PerforQtion Spaces (Line 5). <br /> Perforations Per Laterat = 16 Spaces + � = 17 perfs. Per Lateral <br /> Check tab(e below to veriJy the number of perforations per latera(guarantees(ess than a 10q discharge voriation. The va(ue is <br /> double if the a center monifold is used. <br /> Maximu>n Number of Perfoea[ions Per Laterai[o Guarantea<10�Qischarge Yari.atson <br /> ��.Incn Per orana�z 7/32 Inch pe+-foracio�s <br /> Pipe Diamet�r(InchesY Fe:fora2ion S i Pi Diameter inches) i <br /> Perforat:on Spacng IFee;l 3 (Feeti�� t t� �ti� t <br /> 1 iK 1iZ [ 2 3 <br /> 2 10 13 1& 34 60 2 tt 15 21 3� 68 <br /> z�= & 12 16 28 54 2✓c iQ 1-0 20 32 ba <br /> 3 8 t2 16 25 52 3 4 14 i9 30 6p ! <br /> 3!16 inch Peroraiion; i.`8 Imch Perforatians � <br /> I <br /> Pipe Diar-�.eter{Inchezl Perforation �n Pi Diemeter linchesl <br /> PerforaC�o-i Spacing IFeet) S�� s � � <br /> 5 1u i:_ 2 3 l�eetl ! 1tE 1:2 2 3 � <br /> 2 12 78 25 -ib 8T 2 2T 33 4t 74 1�99 i <br /> Z�^• t2 17 24 00 80 2Jz 2G 30 -st 69 135 <br /> 3 12 16 22 37 75 3 20 29 38 bi 12$ <br /> 7• Total Number of Perforations equals the Number of Perforations per Laterol (Line 6) multiplied by the Number of <br /> Perforated Latera(s (Line 1). <br /> 17 Perf. Per Lateral X �Number of Perf. Laterats = 51 Total Number of Perf. <br /> 8. Catculate the Square Feet per Perforation. Recommended volue is 4-10 ftZ per perforation. "�ra•"°^°'uhu�,°°"> <br /> Does not app/y to At-Grades r�.�o.,��o�,me�� <br /> Head 1(t�� _ <br /> '/� '/re �i.: '/. <br /> Bed Area = Bed Width(ft)X Bed Length(ft) ,.o• o.,e o.., 0.56 0.�. <br /> 1.5 0.22 0.51 0.69 0.9 <br /> 10 ft x 50 ft = 500 ftz 2.0° °.� 0.59 0.� ,.o� <br /> T.5 0.29 0.65 0.89 1.17 <br /> ].0 0.32 0.72 0.98 f.28 <br /> Square Foot per Perforation =Bed Area divided by the Tota!Number of Perforations (Line 7). •.o 0 3� o.� ,.,3 ,..� <br /> S.O 0.4t 0.93 1.36 /.65 <br /> D.vellin A 3/15 irxh ca 1/4 incA <br /> 500 ft2 - 51 perforations = 9.8 ftZ/perforations _'f�� �vertora o�___ _ <br /> Gvrellirrv with t/8 inc�peKoratbm <br /> 2 fee[ O:her escabtN.�ments and'r,STS wit�3�15 <br /> 9. Select Minimum Averoge Head: 1.0 ft �;�h,o,,,;����e�,o�,�bm <br /> 5'eec �a^rr estaC:ishmrnes antl�v5i5 wi:h v8 i�h <br /> �+orations <br /> 10. Select Perforation Discharge (GPM)based on Table ill: 0.74 GPM per Perforation <br /> �1• Determine required Flow Rate by multiptying the Totol Number of Perforations (Line 7)by the Perforation Discharge (Line 10). <br /> 51 Perforations X 0.74 GPM per Perforation = 38 GPM <br />