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2006-P10580 - septic
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2280 French Creek Circle - 10-117-23-23-0003
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2006-P10580 - septic
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Last modified
8/22/2023 3:21:08 PM
Creation date
11/30/2016 2:19:36 PM
Metadata
Fields
Template:
x Address Old
House Number
2280
Street Name
French Creek
Street Type
Circle
Address
2280 French Creek Circle
Document Type
Septic
PIN
1011723230003
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. 3. TRENCH OR BED BOTTOM AREA <br /> H. For trenches with 6 inches of rock below the pipe: <br /> A x F= 900 gpd x 0.83 ft/gpd = 747.0 ft� <br /> I. For trenches wit� 12 inches of rock below the pipe: <br /> A x F x 0.8= 900 gpd x 0.83 ft/gpd x 0.8 = 597.6 fi� <br /> J. For trenche�with 18 inches of rodc below the pipe: <br /> A x F x 0.6�= 900 gpd x 0.83 ft/gpd x 0:66= � 493.0 ft� <br /> K. For trenches witfi 24 inches of rock below the pipe: <br /> A x F x 0.6= 900 gpd x 0.83 fUgpd x 0.6= � 448.2 ft2 <br /> L. For gravity beds witfi 6 or 12 inches of rock below the pipe; <br /> 1.5 x A x F=1.5 x 900 gpd x 0.83 ftlgpd = 1120.5 ft <br /> M. For pressure beds with 6 or 12 inches of rock below the pipe; <br /> A x F= 900 gpd x 0.83 ft/gpd = 747.0 ft <br /> 4. DISTRIBUTION Check ail that apply) <br /> x Bed(<6%slope) Drop Boxes(any slope) x Rock <br /> Tre�ches Distribution Box(<3°�) Chamber <br /> x Pressure Gravity Gravelless <br /> 5. SYSTEM WIDTH,LENGTH AND VOLUME <br /> M. Select width= 15.0 ft <br /> N. If using rock,divide bottom area b width:(H, I,J or I�divided by P=lineai feet <br /> 747.0 ft/ 15.0 ft = 49.8 lineal feet <br /> Rodc depth below distribution pipe plus 0.5 foot times bottom area: <br /> (Rodc depth+0.5 foot x Area H, I,J,K,L) <br /> ( 1 ft+0.5 ft)x 275.0 ft= 412.5 ft3 <br /> Volume in cubic yards=volume in cubic feet divided by 27 <br /> 412.5 127= 15.3 yd3 <br /> Weight of rock in tons=cubic yards 6mes 1.4 <br /> 15.3 x 1.4= 21.4 tons <br /> 0. If using 10"Gravelless Pipe,length=Flow(A)x Gravelless SSF(see figure D-9) <br /> 900.0 gpd x � ft/gpd = 0.0 lineal feet <br /> P. If using a Chamber H, I,J,K ased on height of chamber slats divided by width of chamber in ft) <br /> ft/ ft = #DIV/0! lineal feet <br /> 7. LAWN AREA <br /> Q. Select trench spacing,center to center= 15 feet <br /> R. Multiply trench spaang by lineal feet R x Q=sq.ft.of lawn area <br /> 15 x 49.8 = 747 ft <br /> 8. LAYOUT <br /> Select an appropriate scale;one inch= 40 feet <br /> Show pertinent property boundaries,rights-of-way,easements. <br /> Show location of house,garage,driveway,and all other improvements,existing or proposed. <br /> Show location and layout of sewage treatment system,well and dimensions of ali elevations <br /> I hereby certify that I have completed this work in accordance with all applicable ordinances,�ules and laws <br /> (signature) 810 (license#) 05/16/06 (date) <br /> Page 2 of 2 <br />
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