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septic design (2)-not sure which one went with permit
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3400 Fox Street - 05-117-23-43-0005
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septic design (2)-not sure which one went with permit
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Last modified
8/22/2023 5:22:25 PM
Creation date
11/29/2016 3:03:36 PM
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x Address Old
House Number
3400
Street Name
Fox
Street Type
Street
Address
3400 Fox St
Document Type
Septic
PIN
0511723430005
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, MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. �.OW Estimated Seaage Flow in Gailons per DaY(gpd) <br /> Estimated oo gpd � <br /> N�anber <br /> or measured - X I.J� _ ^ �C�. B�°�� �I �'P�II Type II[ 'Iype IV <br /> 2 300 225 180 6oat <br /> 3 450 300 218 °� <br /> B. SEPTTC TANK LIQUID VOLUMES 4 �ao 3�s zs� .� <br /> �- � �c o gallons 6 9 o sa50s s�z o� <br /> � iaso 60o s�o �,,m,. <br /> 8 1200 675 408 <br /> C. SOIIS (refer to site evaluation) � � u5� �a�� '� N�� „� �� <br /> 1. Depth to restricting layer= 2,a-to a� inches B�� � �, <br /> 2. Depth of percolation tests = 1 a " inches `"�'"' `"�'' <br /> 3. Perrnlation rate 5. � mpi 23 a`;` ,'o�o°o ;;s o <br /> s«b i.soo z.zso <br /> 4. Land slope S % ,a s z000 3.000 <br /> ovc 9 See 6g.C-6 (z 1S) <br /> D. ROCK LAYER DIlviINSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83 = <br /> )�,00 . gpd x 0.83 sq. ft./gpd =��sq. ft. <br /> 2. Select width of rock layer (10 feet or less) _ /C ft. <br /> 3. Length of rock layer = azea=width = Rock Bed <br /> 15 �O sq. ft.i 1Q-ft. _ /oc� ft. �.,•tiN.ti•ti•ti•ti•ti•5�.ti.ti•ti•L•ti•,.ti <br /> t•t.f•I•!•J•t•1•r t•r•t•1•t•J•1• <br /> 1.ti•ti•ti•ti•L•ti.ti•ti•ti•tiK.tiK.\•ti.t L C <br /> 1rti:ti:ti:ti�tif�ftirti:yrti:tirtirtiry�ti�ti ldtll �10!t. <br /> ;fti�tiftiftirti�tirti�1�tirti�tirtir�ftirtif� <br /> •t•f'l•f•t•f•t•J.l•J•t.!•f.r•1•1• __ <br /> E. ROCK VOLUME �- �'g�' -� <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; � <br /> q��sq. ft. x ,�ft. _�� cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> ��cu.ft. 127= 3�� cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> ,�cu. yd. x 1.4 ton/cu. yd. _� tons. <br /> F. ADSORPTTON WIDTH L`'�`� �� '"� n� a,w�a�,s�, Table <br /> 1. Percolation rate in top 12 inches of soil is 5.� mpi P��,ti�,�,� ��. R.�d <br /> �y;,,�,t�,p�;�, SoilTexture �q,�',� �`,"m <br /> (mpil ree .b.ervem <br /> dd� <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 oarse Sand l�o l.00 <br /> d/ft� 0.1 to� Sand 1.20 1.00 <br /> , y� � 0.1 to� Fine Sand" �•� Z•� <br /> 6 to 15 ndy Loam 0.79 1 S2 <br /> 3. Calculate adso tion width ratio b dividin rock la er 16 co so �.oam o.60 2.00 <br /> � }' $ 5' 31 to 45 Silt Loam OSO 2.40 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; �to bo ciay t_,oam o.4s 2.6� <br /> 61 t0120 Clay 024 5.00 <br /> 1.20 gPd/ft2�- •_�gPd/ft2 = a"c�!�. Slower than 120 Cla -- - <br /> "Soil}uving 509G or ma�e of Eux or vcy fine und <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> a.� x�ft = ��.� ft � <br />
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