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�_:EF'�=�=y-•�;=: IJELi 4_i� : 1 � F'P� ELLE'=:THL� LHNL �=:EF"•:' I �-E'=: r. l -•r.:=:'�'��=i4i` F'. Fi4 <br /> �U1VTP�SEL�.�i.TjS��LR�a�,rWr�.�� <br /> A. U�t�rtniz��'�am� s�p��iii�t , <br /> Gr�vlty►r]3striblat3otl [r+A �+��nr�ot+ � a p�RfDf2A7�G LATERA� <br /> �. M9nimum aug�ested�is 800 gall�n�pQr h�ur(]�gpm)tb.st8�y aheas�9f �Qu�,�„ <br /> water use rate. <br /> Tepwq <br /> 2. Maximum$ugg�zstet� for d�lir�ry to a dr�p box of a h�m�system is 2,7p0 <br /> gallons per hnur(45 gpm)to prev�nt build-up of pressure in drop box. •�`` `�,,�,,,s�,,, �,,, ` '',,�x°� a.^����a���rFr�,k�«�,.• <br /> �., - I�rMln�} °"co.nra <br /> Pressure biskribukior► r. tn1eT p��;'�a rw.i:o.�r5ur <br /> v <br /> �. a, Se1ect number of per6orat�d�aterals � T ���• ;� ,� �p���«ro �a4� <br /> b. Se�ect perfora�on s�cing� � ft. �, ; : � , . , <br /> � '..�. ' Ppraanv Lucarw al <br /> �. Subtract 2 ft.frnm the t��k]ayer length. � ° cr,w�,s�� �y„ B4,�oT o�"tat.�� <br /> r„ ,,� -2 fk.� �� ft. <br /> ' �byai�an P+vw+�i s�or���.a <br /> iet�Vlpslnq Dard ayrr <br /> d. Determine thex�umbtt Af�pa�es b�tween perforatibns. <br /> l.e�Rt� perf.spa�in$�.__Sy ft.+�ft•_ �� Sp���S TABL�t'7�rBRW017ATZ0T�!p1SCHAkGFS IN GPM <br /> �. � spaces+ ] * l�p�rf4�'�U4115/l3tftr2tl <br /> " f. Muldply perfor�[i�rsper t�t�ral by nun�ber of later<�,ts to N*ad PQNorationdtametfrpnches} <br /> grt toeal nurr,b,�r of p�rfQratioa,s. y -- �------�-�-� <br /> �. x �_ ���R //�� �rforati�ns. __.__ �� �' -- <br /> �1.0�+ �.56 0.74 <br /> $' r��► x �'� .r"�$Prn• y s a.69 0.40 <br /> •f 2.()b 4-80 I.(14 <br /> 4.5 tl.�9 t.17 <br /> 5E1.��'FEp pL�TMP CA�pA�I?Y ,�_ �� �.0 fl.9g 1,28 <br /> BPm �.o �.ra �,a� <br /> �,4 1,26 1.65 <br /> �. Detetm�ne haad reqn�.ret�cz�ts: <br /> 1. �levation differ�m�ebetween pump�nd po�nk oF�ischar�e. ���2.Di+iof��r��ffii tit�6�ta <br /> g feet <br /> 2• if p�rmping ta a presaurQ dlstribution sysfem,add five feet Eor pres3ure <br /> rec�uired at mantfold <br /> �' ✓� feet � <br /> 3. �riCHor►loss � Pipo I.engih y , <br /> a. Enter friction 1a55 table with gpm anci pipe dfameter. p ni of p;scharga <br /> t2ead fric ion Ic�ss tn feet per 100 f�et from;abte. <br /> F.L. � .� Ft./1flQ ft oF ptpe ElcysEion Difforcncc <br /> b. U�termine tpta!pipe length from pump to dischar};e �p <br /> •po�nt. Add 25 perC�nt to pipe ten�th for fitting � <br /> lass,ar use a EjtCing lass ch�rt. Equivaleni pipe F�lgb <br /> Iength�].25 tEm�pipe length� <br /> t x 1.?S=�Z�_jeEt 1.5 inch 2,0 inoh 3.4 inch <br /> �. Calculate tpt�1 friction loss by multrplying <br /> BPm Fr�a��r,tca per�oa n o�ptyo <br /> frfction IpsS fn It/lD4 ft by eqi�xvalent pip�length. � i� O.y6 0.�8 <br /> Total frfetjon Ioss•• 4�2 x �,.�r +1(}��„��f¢�t 14 1.28 0,38 <br /> a, Total head requfr�,i i9 the�um of er�vation differenc�, �4 1•�� b.a8 <br /> spectal hea�requirements,and total friction 1oss. �8 2•0� 0.60 <br /> 20 2.47 0,73 0.11 <br /> 2S 3.73 l.lf O.I6 <br /> ,�.,��+ � �+ � 3Q 5.23 1,53 0.23 <br /> (1? E2} t3�) 35 7.9a 2A6 4.30 <br /> 40 11.07 2.b4 0.39 <br /> 45 14.73 3 28 0.4$ <br /> TOTAI�HEAp �� feet Sb 3.99 0.58 <br /> 55 4.76 0,�0 <br /> C. Pump seletlIon <br /> � 5.60 0.82 <br /> 1. A purr►p must be selected t� deliver aE least „�, �p�, (Step A) <br /> with at least!'�? #��t of totai he��i (Step �). <br /> . <br />