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septic design-1996
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3345 Fox St - 05-117-23-44-0007
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septic design-1996
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Last modified
8/22/2023 5:22:34 PM
Creation date
11/28/2016 2:15:51 PM
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Address
House Number
3345
Street Name
Fox
Street Type
Street
Address
3345 Fox St
Document Type
Septic
PIN
0511723440007
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' ' MOUND DESIGN WORKSHEET <br /> (For Flows up to I200 gpd) <br /> A. �ONJ Ettimued Sewage Aow�irm Callo�s pa Day(gpd) -� <br /> Estimated '7 So gpd <br /> N�anber <br /> or measured - x 1.5 = - gpd. �°Q,,,,, �'p`I ��I �YP�III �ry�rv <br /> 2 300 225 180 soqc <br /> 3 450 300 218 •r <br /> B. SEP'ITC TANK LIQUID VOLUMES ' � 3�s zs� •� <br /> s �so ,so z� � <br /> �-12�5� � ) -/voc� gdllOI1S 6 900 S7S 332 � <br /> 7 1Q50 600 370 0°" <br /> �.�,. <br /> g 1200 675 408 <br /> C. SOIIS (refer to site evaluation) <br /> x�� �� ,.,�� <br /> 1. Depth to restricting layer = ) a�'�i�`' � i�4inches B °� �� �,,w <br /> 2. Depth of percolation tests = i a" inches `""�' `'"'' <br /> 3. Permladon rate �-� mpi Z;a'4` ,'� ;•,� <br /> 4. Land SlOpe 7 % s«6 i.soo uso <br /> 7 or 8 2,000 3,000 <br /> wa 9 See fi;.C-6 (c IS) <br /> D. ROCK LAYER DIlv�1SIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83 = <br /> �s� gpd x 0.83 sq. ft./gpd = L�a sq. ft.-+�p`��=���,p <br /> 2. Select width of rock layer (10 feet or less) _ /o ft. <br /> 3. Length of rock layer = area i width = R�g� <br /> f�d y sq. ft. + �o ft. _ �� ft. ti.ti�l,y�ti��.ti.".�r��,�,,,� <br /> r•f•r•f•�•�•r•r•r•r•f•i•�•r•�•r• <br /> ti•ti•ti ti•� ti ti ti•�.�.�.ti•ti•t.�.ti•ti <br /> tifti�ti�ti:��ti?ti`ti ti�ti�l�tir1r1f1ftifti �dth 510 ft. <br /> Yfti�ti�ti�ti:ti�ti�ti%ti�ti���ti tir�f��lfti <br /> •f•�•f•r•f•f•r•f•f•r•/�•r•r•f•f•f• � <br /> E. ROCK VOLUME � �'g�' -� <br /> 1. Multiply rock azea by rock depth to get cubic feet of rock; <br /> (,4S�- sq. ft. x l,u s ft. _�„ cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft:/cu. yd. to get cubic yards; <br /> �,cu.ft. i 27=�cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> �cu. yd.x 1.4 ton/cu. yd. _� tons. <br /> F. ADSORI'TTON WIDTH L`-�`� ��y�'�'-, <br /> on Width Sirin Lbk <br /> 1. Percolation rate in top 12 inches of soil is �.� mpi r�oL,«,�,� G°� a�°°°' <br /> 1„ti„�,u,pK;�►, Soil Texture �,� "a,'ed <br /> (mpil i.e .e�.00a <br /> da� <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 oarse Sand 1.2o i.00 <br /> .UJ� d/ft� 0.1 to5 Sand 1.20 1.00 <br /> � 0.1 to 5 Fine Sand" 0.60 2.00 <br /> 6 to 15 ndy Loam 0.79 1 a2 <br /> 3. Calculate adso tion width ratio b dividin rock la er 16 co�o �.,oa�, o.bo z.�o <br /> rP y g Y 31 to 45 sic t.�m oso z.ao <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; �to bo c�ay t,oan, o.as 2.6� <br /> ,/ 61 t0120 Clay 024 5.00 <br /> 1.20 gpd/ft2y r�J gpd/ft� = a,�� Slower than 120 c�a - - <br /> "Soil having 509L or mae d fine or vey fvx sand <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> �x�D ft = a�,7 ft <br />
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