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1996-008099 - new septic system
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3250 Fox Street - 05-117-23-44-0012
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Paper work from old PID#05-117-23-44-0004
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Permits/Inspections
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1996-008099 - new septic system
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Last modified
8/22/2023 5:22:45 PM
Creation date
11/21/2016 11:44:25 AM
Metadata
Fields
Template:
x Address Old
House Number
3250
Street Name
Fox
Street Type
Street
Address
3250 Fox St
Document Type
Permits/Inspections
PIN
0511723440012
Supplemental fields
ProcessedPID
Updated
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MOUND DESIGN WORK5HEET <br /> {For Flows up to IZQO gpd) <br /> -A. FI.OW E����s���e�70«�,c��,:�Dar(aa� <br /> Estimated � � gpd N�« � <br /> 'iype 'IYpe III '!}rpe IV <br /> of pc i tt <br /> or measured ,--� x 1.5 � -~ gpd. s�� <br /> z aoo zzs tso so� <br /> 3 ts0 3a0 21s � <br /> B. SEPTIC TANK LTQUII� VOLIIMFS 4 �0 3�s � <br /> s �so •so z� '�e <br /> (-11 Sr7 4 �—)p D u $du011S 6 400 521 332 � <br /> � I050 b00 370 � <br /> g 1200 67S �Og <br /> C. S�ILS(refer ta site evaluation) r,�,,a ,.,.� „w <br /> 1. Depth to restricting layer= t�c�'�zo�`,Q ��'inches 'r �-;� `�'°.�' <br /> s��ooms G.r, v�D�° <br /> 2 Depth of perco�afion tests= i a'' inrhes """' <br /> 3. Percolation rate `)._5 mpi �s a� t'.SOo°o i's'ouo <br /> 4. Land s2ope '� �Q ,a s � � <br /> v.c 9 Soe fis.G6 (:13� <br /> D. ROCK LAYER DIM�TSIONS <br /> I. Multiply flaw rate by 0.83 tn obtain required area of rock <br /> layer:A x Q.83= , <br /> 7 SJ $pd X 0.$3$Q. {t.�gpd= G�� Sq.ft.-�lo`�s=fes��° <br /> 2 Select width of rock layer(10 feet or Iess) _ /u ft. <br /> 3. L.ength of rock layer=area�width= Rock Bed <br /> �`� .._sq.ft.� r o ft. _�s�ft. . ...,...,.,...�.,.ti.,.,.�,,. <br /> l.INV.t�h/�I.Jd.��I.�t t <br /> \.1 1.'�N.t.ti. +��1•�.t+1.�.�.t <br /> ���ti�{���ti�'-ti ti ti�.'ti{'ti"C{'-r' �dth SIO f� <br /> ��i.�.r.rr�.r•i�•t•�•��i•i•r <br /> �'~'�'~i:i:-ti.�.ti.�•t.t.t-ti.�-�•� <br /> .i.i.�. i.i.�.i.i.i.i.r.r./.� <br /> E. ROCK VOLtJME ~— �'&� � <br /> 1. Muitiply rodc area by rock depth to get cubic feet of rock; <br /> (oYLa sq.ft.x .�f�. _�cu.ft. <br /> 2. Divide cu. ft.by 27 cu.ft./cu.yd. to get rubic yards; <br /> �� cu.ft. �27= a�_cu.yd. � <br /> 3. Mul�pIy cubic yards by 1.4 to get weight of rock in tons; <br /> a� ru.yd. x 1.4 ton/cu.yd. _�tons. <br /> F. ADSORT.'TION'WIDTH `��LC �.o�w, <br /> on WSdth TaDk <br /> 1. Percolation rate ir�top I2 inches of soil is `�•S mpi r,.,ro,a�.u�� �.� ;a„ <br /> ;k;,,�.�p��;, SoilTexture �,T„� ..,r,,, <br /> c �b �►�-,,,�w'" <br /> 2 Select aIiowable soil Ioading rate from table; F$s��,�,o.i oarse sana �2� �m <br /> •`�� SPd�f� o.iios �n s�d� ob0 zo�o <br /> b to�5 ndy i,oam 0.?9 I.i2 <br /> 3_ Calculate adso tion width ratio b dividin rock ta er 16:0 34 l.oam 0.60 2.00 <br /> rp y $ y 37 to 4� sils Loam o� 2.40 <br /> IQading rate of 1.20 gpd/ft2 by allowabie soil loading rate; b�i�o zl Q �a t.oaa► 0.45 2.6� <br /> �lay 024 �.QO <br /> 1.20�d/ftZ-� .� S gpd/ft�= a•t.7 Slower than 12(? Clav ---- <br /> —sd1 rs+��04 ar more at fvx or ra�r fin.ftt,d <br /> 4. Mulkiply adsorptian width ratio by rock layer width to get <br /> required adsoz`ption width; <br /> , .�x L° ft- a��ft f;'� <br /> �r3r <br /> 9'd d�OJ��•IIQ�I�H�3.�105 �b:6e 96, tii Nflt <br />
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