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1997-009455 - new septic system
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3125 Fox Street - 04-117-23-33-0011/12
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1997-009455 - new septic system
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Last modified
8/22/2023 5:12:43 PM
Creation date
11/16/2016 12:13:38 PM
Metadata
Fields
Template:
x Address Old
House Number
3125
Street Name
Fox
Street Type
Street
Address
3125 Fox St
Document Type
Septic
PIN
0411723330011
Supplemental fields
ProcessedPID
Updated
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G. DOWNSLOPjE DIICE WIDTH <br /> "�''� 1. If landslope is � % or less adsorption width inculdes both upslope and <br /> �- downslope widths <br /> 2 Calculate Minimum mound size bsaed on geometery: <br /> a. Determine depth of clean sand fill at upslope edge of rock layer: <br /> Separation l•o feet <br /> b. Multiply rock layer width by landslope i reoc c.�.� <br /> t 1ooE Ro ee <br /> ro determine drop in elevation; <br /> S�p�rotton tt�t ! <br /> Slope Di��1CB StODt Dtff�rtne� � e� <br /> - x -` %y 100 = - feet UDslope W1Ct� ' <br /> c. Add depth of clean sand for separation (2a) -�-'�°� <br /> Rock eea wtatn <br /> at upslope edge,depth of rock layer (1 foot) to �-►«< o o w�s�o�w,e t� <br /> �_reet <br /> d e pth of cover(1 foot) to find the mound height at the <br /> upslope edge of rock layer; l•o ft+ lft + lft= ,�.o feet <br /> d. Enter table with landslope and upslope dike ratio. ' <br /> Select dike multiplier of 5 , c� . s:�s s <br /> e. Multiply dike multiplier by upslope mound height to find <br /> upslope dike wiiith: 3.c� x �.� __1..i feet <br /> f. Add depth of clean sand for slope difference (2b) at downslope edge, to <br /> the mound height at the upslope edge of rock layer (2c) to find the <br /> downslope height; - ft + - ft = - feet <br /> g. Enter table with landslope and downslope dike ratio. <br /> Select dike multiplier of - <br /> � h. Multiply dike multiplier by downslope mound height to get <br /> downslope dike width: - x - - - feet <br /> i. Minimum mound width is the sum of upslope dike width plus rock <br /> layer width plus downslope dike width; o� <br /> - ft+ - ft+ - ft = - feet " <br /> � UDslop N10t� �:.� <br /> j. Subtract the minimum width (2.i) from the -��•'� > j' <br /> .Nv... .... .� ,F<.,.f. ' <br /> adsorption azea (F.4) to find the additional R,�t,.,w,at� <br /> downslope area for adso tion � `"` <br /> � a UDslop,�h'tOtn UPsi�v+iatn <br /> - ft- - ft= - feet 3 �'-`°" �"" <br /> k. Add the additional width (2.j ) to the � <br /> downsolpe width and recalculate yo oo�����ta�� : <br /> the total width ` ' ' `' ' <br /> �_ft+�ft +�,�ft = �• feet <br /> 1. Total mound length is the sum of ` , i: <br /> upslope dike width plus rock layer length ' �� ' ` <br /> plus upslope dike width: T,t,,�,�9t� <br /> 1S ft+�ft+ 1�� ft = � feet <br /> owns ope ps ope <br /> 3:1 L•1 5:1 &1 7:7 3:1 l:] 5:1 6:1 7:1 8A <br /> S�bpe <br /> 0 3A �o s.o �.o �.0 3.0 �.o s.o �.o �.o e.o <br /> 1 3A➢ L37 S1b 6.38 753 291 3.85 {.76 5.66 i54 �.�1 <br /> 2 3.19 L1S 556 6.62 d.1{ 2d3 3.70 !S/ 536 Gt4 6.90 <br /> L� 3 330 4S4 S.d! 7.32 d.l6 275 337 1.35 5.06 5.79 6.15 <br /> { 3A1 L76 6.75 7.D9 9.72 26a J.IS t.17 l.61 5.16 6.06 <br /> S �� S.pp ip l,S7 10.TI 261 733 4.00 t.62 5.19 5?1 <br /> 6 3b6 S.?b 7.14 938 7207 251 327 3A5 lll �.43 SAt <br /> 7 3�0 556 7.69 70.i4 ]3.73 2{8 3.12 3.70 �.27 1.70 5.13 <br /> 8 3.95 S.dB !3� 1154 15.91 242 3.Q3 3S7 4.05 1.19 4�8 <br /> 9 4.11 6.25 9.09 13.0/ 1 d.92 2.36 244 3.15 3.90 !�0 �.65 <br /> �p �,Z9 �67 l0A 15.00 2333 Z.31 2D6 333 375 �.12 �.M <br /> 11 4A6 7.7{ 11.11 17.65 30.0 226 27a 3.23 3.61 3.95 �Z6 <br /> 12 �b9 7.b9 1i50 21.t� t3.75 2.21 270 3.12 l.l9 3.E0 �.06 <br />
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