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,� <br /> � <br /> PUMP SELECTION PROCGDUR[: <br /> A. Determine pump capacity: <br /> Gravity Distribution END PERFORATION OF A PER�ORATED LATERAL <br /> 1. Minimum su�ested is 600 gallons per hour(10 gpm) to stay ahead of �c,a�.�,�., <br /> water use rate. -'`- -`- -� �- <br /> �� ToDwd <br /> 2. Maximum su�gested for delivery to a drop box of a home system is 2,700 ��: -,- ---__�- <br /> �oyer of Gcol�clil� FaDNc (w�ar• <br /> gallons per hour(45 gpm) to prevent build-up of pressure in drop box. . �oomy sa�w�Y�, �;Mh,ar.,,,,�,„,,,,,,�,��., <br /> �_ lh red rosin paper) <br /> ��� <br /> �er rqle c�erni r�-PerWrotiun O�Illvd Nonronially <br /> Pressure Distribution ;������ � ���a ca, �a, ro, <br /> �/.'Plu� AI leucl 12�lo Edpe <br /> 3. a. Sclect numbcrof perforated laterals Lo�a;� F���a.R�� ��`� o� 17xY �oyv <br /> b. Select perforation spacing= ft. ` --P,,,w,,,�„s����,�a oi <br /> c. Subtract 2 ft. from thc rock laycr icngth. c�.a�Sond Loyt� Bai�uni of Lat�rol <br /> -3 , _ <br /> Y����� -2 ft._ -�:., ft. <br /> . orioi�oi son Properly Scanlied <br /> Belore Nlxinq SaM Layer <br /> d. Determine thc number of spaces betwcen perforations. <br /> L.ength perf.spacing= ` ft.+ ft._ ',�, Sp1CCS TAil1.F.0�PGRI'ORATION UISCIIARCGS 1N CPM <br /> e. �� spaces+ 1 =�perforations/latcral <br /> ' f. Multiply perforations per latcral by numbcr of latcrals to Hcad Pcrforation diameter(inches) <br /> get total number of perforations. - <br /> � , <br /> ��r. x �.�-1era1= perfaratiot�s. �" �• _ <br /> 1.Oa 0.5G 0.74 <br /> �it+ <1�{' _`>, ].5 0.69 0:90 <br /> �• p��. X sr��"''..< ..$Pm. 2.ov a.so i.oa <br /> 2.5 0.89 1.17 <br /> SELECTED PUMP CAPACITY ,� 7 3.0 0.98 t.2s <br /> gPm 4.0 ].l3 1.97 <br /> � 5.0 1.26 1.65 <br /> B.Determine head requirements: <br /> aUse 1.0 foot of head for residential systems. <br /> 1. Elevallondifferencebetweenpumpandpointofdisch�lc�e. bUse2.Ufeetofheadforotherestablishments <br /> f � feet <br /> 2. If pumping to a pressure distribution systcm,add fivc feet for pressurc <br /> required at manifold <br /> � feet <br /> 3. FriCtion loss Pipc Length <br /> a. Enter friction loss table with gpm and pipe diameter. � Point of Discl�argc <br /> Read friction loss in feet per ](�feet from table. T <br /> F.L. _ ! �_"�:.` ft./100 ft oF pipe Ele�ation Diffcrencel <br /> b. Determine total pipe length from pump to discharge Pump <br /> point. Add 25 percent to pipc lcngth for fitting <br /> loss,or use a fitdr�g loss ehart. Equivalent pi�e ' F-18b <br /> length-1.25 Hmes pipe length= 1.5 ir,ch 2.0 inch 3.0 inch <br /> �- o�; x 1.25 = %`��'� fcet sPm Friciion loss per 100 ft of pipc <br /> c. Calculate total friction loss by multiplying . �0 0.69 0.20 <br /> friction loss in ft/100 ft by equivalcnt pipc len�th. t2 0.96 0.28 <br /> Total friction loss= ' •" x �' �" +100= �' feet 14 1.28 0.38 <br /> 4. Total head required is the•sum of elcvation diffcrence, 16 1.63 0.48 <br /> s cial head re uirements,and total friction loss. �g 2.03 0.60 <br /> P� 9 20 2.a� 0.�3 o.�t <br /> 2�_., 3.73 1.11 0.16 <br /> � " + + '� '30. ' S.23 '1.55 ' 0.23 <br /> 35 7.90 2.06 0.30 <br /> (1) (2) (3c) 40 11.07 2.64 0.39 <br /> 45 14.73 3.28 ().48 <br /> � -_' S0 3.99 0.58 <br /> TOTAL HEAD �" i feet 55 4.76 0.70 <br /> 60 5.60 0.82 <br /> �'. Pump selection <br /> 1. A pump must be selected to deliver at least .�'r'� gp�n (Step A) <br /> with at least;•'"T� feet of Eotal head (Step B). <br />