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2005-P09396 - new septic
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2920 Fox Street - 04-117-23-31-0018
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2005-P09396 - new septic
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Last modified
8/22/2023 5:11:29 PM
Creation date
11/16/2016 11:05:29 AM
Metadata
Fields
Template:
x Address Old
House Number
2920
Street Name
Fox
Street Type
Street
Address
2920 Fox St
Document Type
Septic
PIN
0411723310018
Supplemental fields
ProcessedPID
Updated
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�lound Design Worksheet (For flows up to 1200 gpd) <br /> � All�boxed rectangles must be entered,the rest will be calculated. <br /> � A. FLOW <br /> hi:Fsfmaied Sewa�pe HoMs�61a1�s PB Dolr <br /> Estimated �gpd(see flgur�A-1) 'H <br /> be�oQ�s f]�I C!�1 Cbs 11 f]�N <br /> or measured 0 x 1.5(safety factor)= 0 gpd 2 � � �� � <br /> B. SEPTIC TANK LIQUID VOLUMES 3 d50 300 218 dihe <br /> Septic tank capaaty 2-1300 gallons(see figure G1) 4 � � � '� <br /> 5 750 45� 294 n ihe <br /> C. SOILS(Site evaluafion data) 6 � � � �� <br /> 1. Depth to restricting layer- 1.5 feet � �� � � �'a�� <br /> 8 1200 675 408 cdmia. <br /> 2. Depth of percolation tests= 12 inches <br /> 3. Texture Loam <br /> 4. Soil loading rate(see Figure D-33 0.6 gpd/ft <br /> Percolation rate 8 to 16 MPI <br /> 5. %Land Slope 6 % n-�: �r���e'�� <br /> P�cal�daaAau Rm <br /> {a�pe Sail7tanxr � Absocvdon <br /> C-1: Se T�k 1n ana �" R'�O <br /> � <br /> li4d 9� P�n' Iiqiad capacaty Fooc tWm 1 c�.s..d i.xo t.00 <br /> Number�f M'imm� d Li ca with vnth�iaposal& �s.�na <br /> Sedro�as C�1��Y B�aB�� lift inside y <br /> 2 ar less 750 ll7,5 lspp 3i� su�� .so z.a <br /> 3 ar 4 14UQ 1500 �ppp �a w 6o c�y o.4s �.e� <br /> 5 or 6 154Q 2250 � � Q■ r,,.a <br /> ?,8 or 9 2Q00 3000 ai a�2o c�.y o.�4 s.oa <br /> � <br /> � <br /> �Ir ebdyrd Ne Irr dh sat M a�r r�Eo�m <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply average design flow(A)by 0.83 to obtain required area of rock layer: Item A x 0.83= <br /> 900 gpd x 0.83 ft gpd= 750.0 ft� <br /> 2. Determine rock layer width =0.83 ft�/gpd x Linear Loadin Rate(LLR)(see LLR chart) <br /> 0.83 ft/gpd X 12 = 10.0 ft <br /> LLR Chart <br /> Pe�k Rate LLR <br /> <120 MPI <=12 <br /> >=120 MPI <=6 <br /> 3. Length of rock layer=area divided by width= <br /> 750 ft/ 10 feet= 75.0 feet <br /> E. ROCK VOLUME <br /> 1. Multiply rock area by rock depth to get cubic feet of rock <br /> 750 X 1 ft= 750.0 ft3 <br /> 2. Divide ft3 by 27 ft3/yd3 to get cubic yards <br /> 750.0 ft3 I 27 = 27.8 yd3 <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> 27.8 yd3 X 1.4 ton/yd3 = 38.9 tons <br />
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