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2010-00713 - new septic
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2630 Fox Street - 04-117-23-42-0027 - New PID
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2010-00713 - new septic
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Last modified
8/22/2023 5:14:24 PM
Creation date
11/9/2016 11:42:06 AM
Metadata
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Template:
x Address Old
House Number
2630
Street Name
Fox
Street Type
Street
Address
2630 Fox St
Document Type
Permits/Inspections
PIN
0411723420027
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� OSTP Pressure �istribution <br /> UNIVERSITY <br /> Minnesota Pollution Design Worksheet OF �INNESOTA <br /> Control Agency .-��;; <br /> 1. Select Num6er of Perforated Lnterats in system/zone: � ��°��� <br /> ������� � Minimum�a .1�� <br /> (2 feet is minimum and 3 feet is maximum spacing) /. perforations spaced 3'apart 2'of r«k <br /> �a�a <br /> 2. Select Perforation Spacing: 3.0 ft oc�_ ' 1z" <br /> '�+5'0'�30 �o-�'c3�d� <br /> � �o�q���o��r.��� 9•of rock� ��DO'��'D�a,+,D0�0� <br /> o q o o'=ECd d�d � � ��o<=�� <br /> 3. Select Perforation Diameter Size 7/32 inch <br /> Perforauon sizinq:'/.`to V�" <br /> F4r(oration s ci :2'to 3' <br /> 4. Length of Laterats =Media Bed Length -Z Feet. Perforotion con not be closer then 1 foot from edge. <br /> 63 - 2ft = 61 ft <br /> 5• Determine the Number of Perforotion Spaces. Divide the Length of Loterals (Line 4)by the Perforation Spacing (Line 2)and <br /> round down to the nearest whote number. <br /> Number of Perforotion Spaces = 61 ft .- ��ft = 20 Spaces <br /> 6. Number oj Perforations per Lateral is equal to 1.0 plus the Number of Perforation Spaces (Line 5). <br /> Perforotions Per Laterat = 20 Spaces + 1 = 21 Perfs. Per Lateral <br /> Check Tabte 1 to verifty the number of perforations per[ateral guarantees less than a 10%discharge variation. The value is double if <br /> the a center manifold is used. <br /> �• Toto!Number of Perforations equals the Number of Perforations per Laternt (Line 6)muttiplied by the Number of <br /> Perforvted Laterats (Line 1). <br /> 21 Perf. Per Lateral X ��Number of Perf. Laterals = 63 Total Number of Perf. <br /> 8. Calculate the Square Feet per Perforation. Recommended vatue is 4-10 ft Z per perforetion. ����pM� <br /> Does not apply to At-Grades ,a„a,,,,,��„�� <br /> Bed Aren = Bed Width(ft)X Bed Length(ft) Head�`� '�. '�,. '�,. '�. <br /> 1.0' 0.1! 0.41 0.!6 0.74 <br /> 10 ft x 63 ft = 630 ft2 +.s a.=2 o.s, 0.69 0.9 <br /> 2,0� 0.26 0.59 0.80 f.04 <br /> I.S 0.29 0.65 O.D9 1.17 <br /> Square Foot per Perforotion =Bed Area divided by the Totai Number of Perforations (Line 7). �-o 0_�2 o.�z o.� ,.�e <br /> s.o 0.3� o.aa �.�s �.�� <br /> 5A` 0.41 0.9] 1.26 1.6� <br /> 630 ft2 .- 63 perforations = 10.0 ftZ/perforations „m� 1/ainchard3/761nchpeAotatfanon <br /> ���,� <br /> 9. Select Mintmum Average Head: 1.0 ft 1/e inch per/oratlau on dvrMlinga and for <br /> z reet ou�er gcaalsl,ments <br /> 1/�fnch aM 3/t6 4rch peforatbix on At515 <br /> 5 fest //8 inch perioracfons on MSTS <br /> 10. Select Perforation Discharge (GPM)based on Table III: 0.56 GPM per Perforation <br /> 11• Determine required F1ow RQte by multiplying the Total Number of Perforotions (Line 7)by the Perforation Dixharge (Line 10). <br /> 63 Perforations X 0.56 GPM per Perforation = 36 GPM <br /> 12. Select Type of Manifold Connection (End or Center): �end ❑Center <br />
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