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OSTP Pressure Distribution <br /> 4� � �� UNIVERSITY � �`` v; <br /> "'���e����°"�tt�, Desi n Worksheet �� ��`z tr <br /> Control A enc � OF MINNESOTA �,`.,� <br /> ProjectlD: v 11.09.22 <br /> 1. Setect Number of Perforated Laterals in system/zone: �� _------` <br /> �--- <br /> (2 feet is minimum and 3 feet is maximum spacing) ""��'tl1e°���",°�x <br /> �� .+` r ��� _ . � . _ -I' `� <br /> 2. Select Perforation Spacing: 2.5 ft � '� " ' ' -'_' S���°��E� ' - <br /> �� -.. / perio�et r � - M �n u r� � .. <br /> �s sp.s�cxJ 3'a�aart�� t 2",0l ruak :77��. -. <br /> 3. Select Perforation Diameter Size 7/32 in _ <br /> .. . 4"�ot rock � . . . � <br /> 4. Length of Loterals =Media Bed Length -2 Feet. �e1*��a���"=;=�"y�,�-_� ,.- �r�to.a=,��=va�,,,y z �.,� <br /> 1 50 - 2ft = 14$ ft Perforation can not be closer then 1 foot from edge. <br /> 5� Determine the Number of Perforotion Spaces. Divide the Length of Laterals (Line 4) by the Perforation Spacing (Line 2)and <br /> round down to the nearest whole number. <br /> Number of Perforation Spoces = 148 ft - 2.5 ft = 59 Spaces <br /> 6. Number of Perforations per Laterol is equal to 1.0 plus the Number oj Perforotion Spaces (Line 5). <br /> Perforations Per Lateral = 59 Spaces + 1 = 60 Perfs. Per Lateral <br /> Check tab(e below to verify the number of perforations per latera!guarantees less than o 10%discharge voriation. The value is <br /> double if the a center manifo(d is used. <br /> Maximum Number of Ferforatio�s Per Later�l to Guarar�t�e�9�e DischargQ Variation <br /> �,l� Pertorahons 7/3?Inch Perfararians <br /> Ferfarat�on Spa�n$�F�tj Fipe Dieme#Er llnches) Ferfa.raEion Spacing Pipe Diameter(Inches) <br /> - � !�a 1ih 2 3 �Fe�#} i 1�a 1�i 7 3 <br /> � i4 13 i8 30 b{? 2 !1 i6 21 �4 68 <br /> 2i"� $ 12 1G 2$ ,4 2I� 1Q 9� 20 32 64 <br /> � $ i� i� 25 52 3 9 14 ig 3Q 6Q <br /> 3f961nch Pa�ara#ions 9,��1r��'erfor�ti�ns <br /> Pipe daart�ter�l�,:hes� Ferfaration S Pi E?iame��r inches <br /> PerfwaE%on Spac�n�g(Feet) �"� � �, � <br /> # !'� iYz � 3 (Feet} t i� �y� 2 � <br /> 2 9� 1� ?� �� � 8T 2 21 3a �4�# 74 44� <br /> 2�'� 12 97 24 �U 80 2Y4 2Q 30 4� b9 135 <br /> � 9� �� 2� 37 75 3 2i9 29 3$ 54 �28 <br /> 7• Toto(Number of Perforations equals the Number of Perforations per Laterol (Line 6)multiplied by the Number of <br /> Perforated Laterals (Line 1). <br /> 60 Perf. Per Lateral X �Number of Perf. Laterals = 60 Total Number of Perf. <br /> 8. Catculate the Squore Feet per Perforation. Recommended va(ue is 4-10 ftz per perforotion. P•����•�o�r���� <br /> Does not app(y to At-Grades Parfor�tbn Dlametar <br /> H�ad(tq <br /> Bed Area = Bed Width(ft)X Bed Length (ft) �' �''° �'" ''' <br /> 1.0' O.1B 0.�1 0.56 0.74 <br /> 1.5 0.22 0.71 0.69 0.9 <br /> 10 ft X 150 ft = 1500 ft� 2O° o.� 0.59 0.� ,.o. <br /> 2.5 0.29 0.65 0.89 1.17 <br /> 3.0 Q32 O.7y 0.98 1.28 <br /> Square Foot per Perforation =Bed Area divided by the Tota(Number of Perforations (Line 7). •.o 0.3� o.B3 ,.,3 1.47 <br /> 5•0` O.N Q93 1.26 1.65 <br /> 1500 ftZ - 60 rforations c C � ,f�� �«�^�'^^�h 3/16 inch to 1/6 inch <br /> � 2J.� ft /perforations peRoratbns <br /> Dwelli�wi[h 1/8 irich peAora[io�s <br /> 9. SelectMinimumAverogeHead: 1.0 ft z+�� aherataMishmentsandMSTSwith3/16 <br /> imh to 1/4 inch pedoratiors <br /> 5 f�i a�er a[aDllshments anA MSTS wlc�ti6 inc� <br /> 10. Select Perforotion Discharge (GPM)based on Table IIi: 0.56 GPM per Perforation P�orations <br /> 11. Determine required F(ow Rate by multiplying the Tota(Number of Perforations (Line 7)by the Perjoration Discharge (Line 10). <br /> /,S�o� � <br />