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� 1 i <br /> � �IO�liND DESIGN WORK SHEET(For Flows u to 1200 d) <br /> A. Average Desigll FLOW A-1: Estimated Sewage Flows in Gaitons per Day <br /> nu r o <br /> Estimated 7 �� gpd (see figure A-1) bedrooms Ctass I Class II Clau III Class IV <br /> or measured — x 1.5 (safety facfor) _ — gpd 2 300 225 180 � <br /> 3 � 450 300 218 ofthe <br /> 4 600 375 256 values <br /> B. SEPTIC TANK Capacity 5 750 4so 294 in the <br /> 6 900 525 332 Class I, <br /> a- �zS� gallons (see figure C-1) � �� � 3�o n, or ui <br /> � - t��� �,��,,,�� G���,�,�- 8 1200 675 408 columns. <br /> C. SOILS (refer to site evaluation) c�: se ticTank Ca acities fin allons <br /> ��'�`�� ��S4►•'d liquid capacity <br /> Number of Minimum Liquid Liquid capacity with W��disposal& <br /> 1. Depth to restricting layer= �. I �3. 1 feet B���� �P���Y garbage disposal li8 inside <br /> 2. Depth of percolation tests = 1-o feet Za�� �so >>zs 15� <br /> 3. Texture c.��{ L-o,�-w� sa6 is�oo iso 200° <br /> Percolation rate �a.to mpi �,s�9 Z000 3000 300° <br /> 4. Soil loading rate ��� gpd/sqft(see figure D-33) <br /> 5. Percent land slope '� % <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply average design flow (A) by 0.83 to obtain required rock layer area. <br /> 7S� gpd x 0.83 sqft/gpd = t�-z� sqft-�1���,=co�ya' <br /> 2. Determine rock layer width = 0.83 sqft/gpd x linear Loading Rate (LLR <br /> 0.83 sqft/gpd x -�a evd/sqft= �� ft Mound LLR <br /> 3. Length of rock layer = area=width = <br /> V�_sqft (D1) -:- t u ft �D2� -� ft < 120 M PI < � 2 <br /> E. ROCK VOLUME > 120 M PI < 6 <br /> 1. Multiply rock area (Dl) by rock depth of 1 ft to get cubic feet of rock <br /> Co�S y sqft x 1 ft = ��4_cuft <br /> 2. Divide cuft by 27 cuft/cuyd to get cubic yards <br /> lo4S y cuft +27 cuyd/cuft = as cuyd <br /> 3. Multiply cubic yards by 1.4 to get Ynieight of rock in tons <br /> �cuyd�z 1.4 ton/cuyd =_� tons <br /> ��'�`"""" '""""'" ' D-33: AbaorpUon Width Sizing Table <br /> F. SEWAGE AH�QR�T�ON WIDTH `�� � �����«��� Lwdina Rate <br /> `'fA in Minute:per Sal Texture Gdlons Absorp�ion <br /> .,,� � � �h Pa day per Ratio <br /> Mp� uatt foot <br /> Futcr than S Cwrse Sand 1.20 1.00 <br /> Medium Su�d <br /> Absorpdon width equals absorption ratio (See Figure D-33) �ys�^° <br /> times rock layer width (D2) '` ,6� o �,,,, o.�o Z.o� <br /> 1�o as i�i .so 2.ao <br /> .107 x /C� ft = aCo.� f t �s�0 6o s,�,ay o,y o.as z.6� <br /> Silt pay Lo�m <br /> 61�0 120 Silty Qay 0.24 5.00 <br /> S�ndy Q�y <br /> lowetlhin 120' <br /> •Syium dui�tned for Nex oi4 mw be pbsr er perfomruce <br />