Laserfiche WebLink
� � . �. ' . � . PUMP SELECTTO�I`�'�I�Tt��C�D�RE � <br /> 1. D etermine pwnp capaciiy: � <br /> A. Gravity d�stribution . . <br /> 1. Minimum required'discharge is 10 gpm � � <br /> 2. Maxumim suggested'discharge is 4S gpm. For other� � � � <br /> establishzn�nts at Ieas�10°�o gre�te'r�hazi the water supply rate, <br /> but no`faster than the rate at wh{ch effl�ient will flow out of the � <br /> disttibufion device. . � � � <br /> B. Pressure distribution . " ' � � <br /> See pressure�dz,stribution work sheet � <br /> From�A or B Selected�pump capacity:=gp� : <br /> 2. Determine pump head�requiremen#s: . . <br /> A. Elevation differerice between pump and point of discharge? • � soil treatment syst <br /> � �i' feet , . . ' &p int f ischar <br /> :Q��.�4�,b��.Qyi. <br /> B. Special head requixement? (See Figure at righf-Special Head Requi'reznents) , total (pe �s) <br /> S feet . , . len�t � <br /> � � Inlet � ' ��e�evatlon <br /> C. Calculate Friction loss � , p�pe difference <br /> 1. Select pipe diameter �•� ir► � ' ' � ��� � <br /> , <br /> , .. ...••...................... 2 <br /> �'13 <br /> 2. Enter Figure E-9 with gpm(lA or B)and pipe diameter(Cl). , � <br /> Readfrictionlossinfeetperx00feetfromFigureE-9 ' Spectal Head �Requ(rements <br /> Friction Loss = �_to ^ft/•100ft of pipe Gravity Distributlon 0 ft <br /> 3. Deternune total p�pe length frorri�pump discharge to soil treatment :pressure Dlstr(bUtion 5 fit <br /> discharge point. Estimate by adcling 25 percent to pipe length for • . <br /> fitting loss. Total pipe length times 1.25=equivalent pipe length ' ' <br /> '�l C7 feet x 1.2� = a1�3 feet • � �-9: FrlctJon Loss tn Plastic Plpe - <br /> 4. Cal'culate total friction loss by multiplying friction loss (C2) • Per 10o test <br /> in�ft/100 ft.b ,the e uiyalent. i e�Ien . • nominal <br /> Y Q p'p gth(C3) and divide by 100. pIpe d�ameter <br /> — �•lo ft/100ft x a b � y+1 0 0�_�f t ' flow rata I.5" 2" 3" <br /> • m <br />�. Total head required is.tlie sum of e7evation difference(A),speaal'�' 20 ' 2,47 0.73 0.11 <br /> head requirements.($), and total friction Ioss (C4) 25 3,73 1,11 0,16 <br /> ) �� ft+_ 5 � ft+-�_ ' . 30 5.23 1.55 0,23 � <br /> Total head: �.'�) 'feet 35 6.96 2.06 0.30 <br /> � • 40 8,91 2.64 0,39 <br /> . I'urnp selection � 4� � 11.0? 3,28 O.aB <br /> � 50 13,46 3,99 0.58 <br /> A pump must be selected to deliver at ieast . 3� � •Qvm • g� 4,76 0,70 <br /> "j 60 5.60 0.82 <br /> (1A or B) with at least�_feet of total head (2D) ' 65 6.48 0.95 <br /> . . 70 7,44� 1,09 <br /> I hereby certif.y that I have completed this work in accordance with applicable ordinances, •.rules and laws. <br /> � � ��- � ' ' (sig�rtature) 3� y (license#) — a•-0�- date <br /> � ) <br />