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2010-00392 - septic
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2010-00392 - septic
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Last modified
8/22/2023 5:13:28 PM
Creation date
10/19/2016 3:27:58 PM
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x Address Old
House Number
2400
Street Name
Fox
Street Type
Street
Address
2400 Fox St
Document Type
Permits/Inspections
PIN
0411723410011
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MC�UND IjESIUN WORK SHEET (For Flows up to 1200 gpd) <br /> A. Average Design FLOW A-1: Estimated Sewage Flows in Gallons per Day <br /> num er o <br /> Estimated �)a 11 gpd (see figure A-1) bedrooms Class I Closs II Class III Class 6V <br /> or measured " x 1.5 (safety factor) _ -- gpd 2 soo 225 �8o bo% <br /> 3 450 300 218 ofthe <br /> 4 600 375 256 values <br /> B. SEPTIC TANK Capacity 5 750 450 294 in the <br /> 6 900 525 332 Class I, <br /> �� -1 ��..���> gallons (see figure C-1) � ��� �0 3�o ii, or iu <br /> � , �,., �,�� ,c,��.�,�,;� f��•�y,,,,�;�T-.,*�. 8 1200 675 408 columns. <br /> C. SOILS (refer to site evaluation) C-1: Se ticTankCa acilies(in allons <br /> Number of Minimum Liquid Liquid capacity with Liquid capacity <br /> ' Bedrooms Ca acit wilh disposal& <br /> 1. Depth to restricting layer = �,��g �, � feet P y garbage disposal lift inside <br /> 2. Depth of percolation tests = /. c� feet z��iess �so >>Zs isoo <br /> 3. Texture G��A�� �..o�,,,y� 3or4 10°° �s� z000 <br /> 5 or 6 1500 225p 3� <br /> Percolation rate I'--1, 1 mpi �,8 or 9 z000 3000 <br /> 4. Soil loading rate .'�-�.� gpd/sqft(see figure D-33) <br /> 5. Percent land slope �o % <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply average design flow (A) by 0.83 to obtain required rock layer area. <br /> '� �U gpd x 0.83 sqft/gpd = ��r ',� sqft <br /> 2. Determine rock layer width = 0.83 sqft/gpd x linear Loading Rate (LLR <br /> 0.83 sqft/gpd x 1 �, gpd/sqft = / � ft M�und LLR <br /> 3. Length of rock layer = area = width = <br /> �.� �� a. sqft (D1) = 1 v ft (D2) _ � �). ft < 120 M PI < 12 <br /> E. ROCK VOLUM:E > 120 M PI < b <br /> l. Multiply rock area (D1) by rock depth of 1 ft to get cubic feet of rock <br /> �>`>. sqft x 1 ft = �.���,`� cuft <br /> 2. Divide cuft by 27 cuft/cuyd to get cubic yards <br /> ll.-�, �_ cuft = 27 cuyd/cuft = �''� cuyd <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons <br /> � '� cuyd x 1.4 ton/cuyd = "`� �. tons <br /> D-33: Absorption Width Sizing Table <br /> F. SEWAGE ABSO�RPTION WIDTH PerColelion Rate Loading Rate <br /> m Minutcs per Soil Tczture Gailons AGsorp�ion <br /> Inch �cr day per Ratio <br /> MP� s uare(oot <br /> Fastcr than 5 Coarsc Sand 1.20 1.00 <br /> Medium Sand <br /> Absorption width equals absorptaon ratio (See Figure D-33) LoamySend <br /> times rock layer width (D2) Fin Sand <br /> 16 to 30 Loam 0.60 2.00 <br /> 31 io 45 Silt Loam 0.50 2.40 <br /> '� � � 46�0 60 Ssndy Qay Lo 0.45 2.67 <br /> ' X �I`) — �� _ ��•4�?�/� �t Silty Clay Loam <br /> �iny lra <br /> 61 to 120 Silly Clay 0.24 5.00 <br /> Sandy Clay <br /> Cla <br /> Slowcr than I20• <br /> •sys��R,a�,����e rar me5 ,o�i:�:�n�om�r or p�.ro�„� <br />
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