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ONls/T�1 <br /> s�.,.,.�� - Job#� <br /> TREATMtNT <br /> Pwaoucw�e <br /> Universi of Minnesota Mound Design Worksheet <br /> Greaterthan 1yL Slopes <br /> A FLOW <br /> Estimated 750 9Pd(see 6gure A-1) <br /> or measured x 1.5(safety fada)= 0 gpd <br /> B. SEPTIC TANK LIQUiD VOLUMES <br /> Septic tank c�pacity 225p gallais(see figure Gi) <br /> Number of tanks/oar�arhnents 0 <br /> Effluent Fiter (yes/no) yes <br /> C-1 Septic Tank Capacity in Galbns <br /> Number of Minimum Capadty with Capacity with <br /> Bedrooms Capacity Gaib.Disp. Disp.and Lift <br /> 2 or less 750 11 5 1500 <br /> 3 or4 1000 1500 2000 <br /> 5 or6 15d0 2250 3000 <br /> 7,8 or 9 2000 3000 4000 <br /> �. SOILS(Site eveluaGon data) <br /> 1. Depth to resUicxing layer= 2.1 feet <br /> 2 Depth of percotation tests= 12 inches <br /> 3. Texture loam <br /> 4. Soil loading rate(see Figure D-33) 0.60 9P�� <br /> Percolation rate 3 MPI <br /> 5. %Land Slope 7.0 % <br /> D. ROCK LA1fER DM�IENSIONS <br /> 1. Muftiply average design flow(A)by 0.83 to obtain required area of rodc layer:tt�n A x 0.83= <br /> 750 gpd x 0.83 fi�/gpd= 630 ft <br /> 2. Detertnine rock tayer width =0.83 fl/gpd x Linear L.oading Rate(LLR)(see LLR chart <br /> 0.83 it�/gpd x i2.00 = 10.0 ft <br /> LLR Chart <br /> Perk Rate LLR <br /> <'120 MPI <=12 <br /> r_12p MPI <� <br /> 3. Length of rock layer=ar�a�ivided by width= <br /> 630.0 it� / 10.0 fee4= 63.0 ft <br /> E ROCK VOLUME <br /> 1. Multiply rodc area by rock depth tia get cubic ieet of rock <br /> 630.0 X 1.0 ft= 630.0 ft� <br /> 2. Divide fC�by 7T ft�to get cubic yards <br /> 630.0 tt� / 27 = 23.3 yd3 <br /> 3. Muttiply cubic yards by 1.4 to get wei�ht o�rock in tons; <br /> 23.3 yd3 X 1.4 tonl� = 327 tons <br /> Page 1 of 5 <br />