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1745 Fox Street - 03-117-23-44-0009
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Last modified
8/22/2023 4:39:09 PM
Creation date
10/11/2016 3:08:14 PM
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x Address Old
House Number
1745
Street Name
Fox
Street Type
Street
Address
1745 Fox St
PIN
0311723440009
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. MOUND DESIGN WORKSHEET <br /> � (For Flows up to 1200 gpd) <br /> A. �,ONJ Ettimuod Sew�ase Flow in Galloc�s pa Day(gpQ) . .� <br /> Estimated /o Sc� gpd <br /> N�anber <br /> or measureci - x 1.5 = - gpd. s��t„s �`' �'P`u �ry�►t� �ry�rv <br /> 2 300 27S 180 6oa� <br /> 3 450 300 218 °� <br /> B. SF1''ITC TANK LIQLTID VOLUMES � 4 �0 3�s u� ,� <br /> 5 750 450 294 � <br /> - On0 g�0I1S 1 - 1�SO Qj I-1bc�c7 6 900 525 332 � <br /> Hv+-�5�. 7 1Q50 600 370 �� <br /> LtFR�- �c�'_ �^'�4\�-\ 8 1200 675 408 <br /> C. SOIIS (refer to site evaluation) � � <br /> ,r „ �� N�bc y�T� �.,�a <br /> 1. Depth to restricting layer = ��,�o � a� inches B� �,, �,, <br /> 2. Depth of percolation tests = �a inches `'""'' `"""' <br /> 3. Permlation rate �•q mpi 2;a`� ,'� ;�,� <br /> 4. Land slope 370� ���o % 7 a a � ��0000 <br /> wc 9 See fi;.C-6 (a 1S) <br /> D. ROCK LAYER DIIv�IVSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83 = <br /> �d.So . gpd x 0.83 sq. ft./gpd = ��_ sq. ft. <br /> 2. Select width of rock layer (10 feet or less) _ /o ft. <br /> 3. Length of rock layer = azea y width = R�g� <br /> ��sq. ft. y �o ft. _�Z ft. ,.�.,.�.,.,.�.�.�.,.,.,.,.^*-�.;� <br /> r•r•r•r•�•r.�.f•f �•t•l•1•f•t•1• <br /> ti.�•�•ti•�•ti•�•ti•ti•ti•ti•ti•ti•ti•�.�•ti <br /> ��tif�ftiftifti��.r{rti�tifti�ti tiftir�f�fti �dth 510 ft. <br /> .f.f.f.f.f.f.f.f.r.f.f.�.,..f.f.f. <br /> �•�.�•ti•�.ti.�•ti•vti.��ti.ti•�•�•�•ti <br /> .f.f.r.t.f.f.f.f.�.r.r.�.f.f.r.f. <br /> E. ROCK VOLUME �- �'g�` � <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; � <br /> �,sq.ft. x i•�ft. _�cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> ,y�cu. ft. -c-27=��cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> �_cu. yd. x 1.4 ton/cu. yd. _ �� � tons. <br /> F. ADSORPZZON WIDTH �-`'A`� �°�"`1'� �«,w�a�,s�, Lble <br /> 1. Percolation rate in top 12 inches of soil is ��q mpi ��o,,h�,R„� ��. A.�d <br /> l,.ti„t,u,pR;�, Soil Textune �� "d,'ed <br /> (mpil �.. .s.>yonn <br /> Mdd� <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 oarse Sand l.zo i.00 <br /> 0.1 to 5 Sand 1.20 1.00 <br /> � LI f gpd/ft� 0.1 to 5 Fine Sand� 0.60 2.00 <br /> 6 to 15 ndy Loam 0.79 la2 <br /> 3. Calculate adso tion width ratio b dividin rock la er 16 co�o �,o�, o.bo z.00 <br /> � Y g Y s� co as s>>c t.oam oso z.ao <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; �to bo cta �oan, o.as 2.6� <br /> 1.20 gpd/ft2i ,�.f gpd/ft� = a• �� sioWe����Zo ciay osa �.00 <br /> "Soil Fuving 509G or more d tux or vay fux sand <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> ��x�ft =� �.�ft <br /> � <br />
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