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� f��ti��Fk ( S B,e�
<br /> , E-19
<br /> MOUND I)ESIGN WORKSHEET
<br /> (For F �ws up to 1200 gpd)
<br /> A. FLOW D-7
<br /> Estiinated �S� gpc (see pages D-7 or I-3 4 5) �`+TIIAATED S[WAGE FLOWS IN GGLIDNi FE�pAY
<br /> � � IuuOEi� `1 rPC 0(nEA�tNCE°
<br /> or —
<br /> or measured � '�. UEDROOMS � u —m�- ` [u__
<br /> 2 300 223 100 GOx
<br /> 3 �Do ]Oo 2�0 or
<br /> � 600 J7] 25G vol�c�
<br /> 13.� SEPTIC TANK LIQUII � VOLUMES ° "° "° 29�' �>p���
<br /> 8 900 52� 3![ II.�
<br /> 7 1050 5qp SIU p1
<br /> �Z.S� f �Of/O gallons ;see pages C-3 or G5) e izoo sn +oe c i�,'��„
<br /> 'f /ZSG CjIL[G.✓ �L//NOiNG T�IN•� C-�
<br /> �. SOILS �I�eleT� tO Slfe �Va�Uc1f1OI1� SEPTIC TANK CAPACITIES, IN GALLON$
<br /> LIOUIO C�P�CITY
<br /> 1. Depth to restrictin;� layer = 6 inches ���� WNIYUY w„�a.��.oE
<br /> IIED1100Y! UOUID C�PACrtT UiSP03�\
<br /> 2. Depth of percolati<�n tests = / 6 inches ,�„��, ,,, ,,,,
<br /> 3. Percolationrate_ �I. 2 mpi /R/M/�yJ'/TF ��p• ,,,, „oo
<br /> 4. Land slope �; % '�"• ,•"' „'�
<br /> 1.�.OR 0 �ao0 l000
<br /> D. ROCK LAYER DIMEN�IONS
<br /> 1. Multiply flow rate �y 0.83 to obtain required area of rock
<br /> layer: A x 0.83 =
<br /> 7so gpd x 0.83 sq. ft./gpd = �LS sq. ft.
<br /> 2. Select width of roc': layer (10 feet or less) _ /o ft.
<br /> 3. Length of rock lay: r = area �- width =
<br /> 1 S sq. �t. -�- / o ft. = 6Z.S ft. Rock I3ed
<br /> . l•l.f.f.f.f,f,,r,l l�l,�r�j,� I
<br /> 1,.1.ti.ti.'�.ti•ti•ti•ti•1,•ti•'V,•},••,•ti•
<br /> •f.f•f•f•f•f•,f•,/,,r•f,J,f•f,f,:
<br /> ti•ti•ti•ti.ti.ti.ti.ti-ti-ti.ti•ti•ti•ti.ti• Wicllh SIQfI.
<br /> .f.f.f.f.r.f.f.f.f.l.r.l.r.f.f
<br /> . ti.ti.ti.ti.ti.ti.ti.ti.ti.•,.ti.ti.•,.•,.
<br /> •f•f•f•:•,r.f•,r•l•f.l.l•f•l•:•f
<br /> i�. ROCK VOLUME �— Len�;th �
<br /> 1. Multiply rock are.�by rock depth to get cubic feet of rock;
<br /> �z s Sq. :-:. x / ft. _ �2S cu. ft.
<br /> 2. Divide cu. ft. by :'_7 cu. ft./cu. yd. to get cubic yards;
<br /> 6'ZS cu. ft. -:- 27 = Z.�. /scu. yd.
<br /> 3. Multiply cubic y�►rds by 1.4 to get weight of rock in tons; �
<br /> Z.3. �S cu. yd. :< 1.4 ton/cu. yd. =.�Z. Ytons.
<br /> P. ADSORPTION WIDT)�i
<br /> 1. Percolation rate in tc��� 12 inches of soil is `�• Z. mpi E-16
<br /> 2. Select allowable soil loading rate from table on page E-16; •LLow•o«<o.�a„�,o.=��S��o�„��„o=
<br /> u f F o. Go. gpd/f t2 �.,.�.,��, —Ne::�.—b:��.;.�: -- -- ----
<br /> ,,.,,�.,�.,.,.
<br /> 3. Calculate adsorption ��idth ratio by dividing rock layer _�'°"" anam� '_i,'i�.r _�.�•�• _�.r. .�,,,.
<br /> loading rate of 1.20 g��d/ft2 by allowable soil loading rate; ��. � �,� }�� .�� ''�
<br /> , .,, o,. ,.,. ,,, ,
<br /> ,. .�o a.o 0 0. ,,. ,o0
<br /> „ ..� a,o o.o ,e� ,.�
<br /> 1.20 gpd/ft21 c�. 6o gpd/ft2 = �. a o " ..° °.. °,_ ,°, °.,
<br /> �i •u0 o.t� a.D� o.ue e.ou
<br /> Check th;�� value on page E-16.
<br /> 4. Multiply adsorption �vidth ratio by rock layer width to get
<br /> required adsorption �✓idth; �
<br /> 2. ao >: io ft = ZD ft
<br />
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