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, � PUMP SELECTIOI`�T�PROC�DIJRE� ' <br /> 1. Dete-ramine pump capacity: <br /> ��w�� '�" vZ <br /> ,�-...A. Gravity d�istribution <br /> 1, Ivl;nimum'required discharge is 10 gpm . <br /> 2. Maximum suggested'discharge is 45 g�m. For other <br /> establishzx��nts at:least 1�%:�re�ter thazi the water supply rate, <br /> but no fastez than the rate at which effluent will flow out of the . <br /> distribution device. � • <br /> B. Pressure distribution � <br /> See press,u.re distribution work sheet <br /> From A or B. SeIected'pump capacity: 5� _gpm <br /> 2. Determine pumg head;.requirements: <br /> soil treatment system <br /> A. Elevatiozi difference between pump and point of discharge? � &polnt of discharge <br /> feet Q�p4°�a°:ae � <br /> , � ' aeA = � <br /> ----1---- <br /> total pipe <br /> B. Special head requirement?(See Figure at righf-Specidl Head Requirements) � lengt <br /> feet 2A,elevatlon <br /> _ �S _ Inlet • difference <br /> � <br /> � C. Calculate Friction loss � pipe a <br /> 1. Sele�t.pipe cliameter' �• in .....� -------------------------- ------��� <br /> 2. Enter Figure E-9 with gpm(1A or B) and pipe diameter(C1). ' " <br /> Readfriction,lossinfeetper100feetfromFigureE-9 SpecTal `Head Requirements <br /> �,�ft/�100ft of pipe Gravity Distribution 0 ft <br /> Frictiori�Loss=� • � Pressure Disfribut(on 5 tt <br /> 3. Determine total pxpe length fram pump discharge to soil treatment : . <br /> discharge point.Estimate by adding 25 percent to pipe length for <br /> fittin loss. Total pipe length times 1.25=equivalent pipe length ,E-9; Fr(ction Loss in:Piostfc Pipe <br /> �feet x 1.25 = � 1pl feet - Per 100 feet <br /> 4. Cal`culate total friction loss by multiplying friction loss (C2) nomtnot <br /> in ft/100 ft,by.the equivalent.pipe length (C3) and divide by 100. � pipe diameter <br /> tiow rate 1.5" 2° 3" <br /> - �-). S ft/100ft x / a % +100= .=ft m <br /> D. Total head required is.the sum of elevation difference (A�,special�� 20 2;47 0.73 0.11 <br /> 25 3.73 1.11 0,16 <br /> head requirements.($),and�total friction loss (C4) 30 5.23 1.55 0,23 <br /> 1 � _.ft+ . � _f�+ r _.ft= 35 6.96 2.06 0,30 <br /> Total head: a �feet ao s.9� 2.ba a39 <br /> 45 11,07 3.28 0,48 <br /> 3. Pump selectiOn 50 13,46 3.99 0,58 <br /> 55 4J6 0.70 <br /> A pump must be selected to deliver at least__��p� 60 5.60 0.82 <br /> (lA or B) with at least�_feet of total head (2D) 65 6.48 0.95 <br /> . 70 7.44 1.09 <br /> I hereby certify that.I have completed,this work in accordance with applicabl�ordinances, :�rules and laws. <br /> r 3 ai license#) "1-13�'p3 (date) <br /> �� � F <br /> � � (signature) �I � � <br />