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' ' � MOUND 1�ESIGN WORKSHE�T !�y� ��X 5'1�
<br /> • (For Flows up to 1200 gpd)
<br /> t�. �.Ow � rauu�+tn+�:ww»acFluw�wC� , ,>µcr<'..,
<br /> ` Estimated �s� gpd � �e.G�'�"�-'-►�.� :����.�_�,___ ,
<br /> trwnbr� ilyycl ;i�t! 7>� 1}, . -
<br /> i�
<br /> or measured x 1.5 = gpd. i �
<br /> o�` �- -- �-�--__
<br /> z xiu� -�s i��, ! �.{.
<br /> B. SEPTIC TANK LIQUID VOLUMES a ��7^a-''"�'—'� ,l.�.. �t����,�;'� I :��a �tz � ViWK.
<br /> y�1�,'����!ga�l�� � ��� �� � 4-.t.n.+ �]U �� �u
<br /> �
<br /> �� G � �� ,__S.� � xk� � ,.� !s' � T�1� r
<br /> �� 7 " �li�� ! :M�, 3 ' U,,
<br /> � � l� � <'� .�, �,:
<br /> C. SOILS (refer to site evaluation) _ � - ..,.,.,.,.... .�..""
<br /> 1. Dzpth to restricting layer= �--�'� inches �• � feet ����'`"`" '"`"'" ��.
<br /> , ���,.
<br /> Nunnu�A M1w.�ww4.��rJ r_. .we�.rww� j �•�.�.4i.,--.
<br /> 2. Dzpth of percolation tests = /2- inches ��u �f •��-�.�� � .�w..� '
<br /> 3. Texture ��A rn Percolation rate�mpi 2i1"` "° " � ""
<br /> � �„�u :,:,,.
<br /> -�. Land slope ��,, o % �f h ��W `l ,._.., M._._._
<br /> 7�Y �.4W —��i('.� +w.i
<br /> D. ROCK LAYEIZ DIMENSIONS y ` w'"���
<br /> 1. I�fultiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 � �, �
<br /> '���gpd x 0.83 sq. ft./gpd = z 3 sq. ft.� s;� �. t��w �'� �
<br /> 2 Select width of rock layer (max 10' if<120 mpi max 5') _ /a tt. +
<br /> 3. Length of rock layer = area -width = r a•� —� �_�- .� �
<br /> L [ /� � L n o ��, o n y� '=---��-=�,•
<br /> �ij .3C) .S(�. lt. T �L�lt. � 11J �-� lt. "^J-�oofU.a.fGJ�C�D``-0o� O.'i�y+....,Q+.1�..+.- ..rw..w.• ! .
<br /> C o d �
<br /> i n�dA., n Op.o�,G D�ll � '"" � .
<br /> L 9 yA � '4Y"'7'..µ ��.
<br /> Width�ft °`�=�-��.;.�?::_�:..�..�..:
<br /> <120mpi <10' Len`;ch C.`-.._ '.�t �
<br /> >120mpi <5' � � �
<br /> E. ROCI< VOLUME ,
<br /> 1. Multiply rock area by rock depth to get cubic feet of rock;�a��' sq. fr. x l�/�� �
<br /> � ;
<br /> ft. _ �� cu. ft. �
<br /> 2. Divi3e cu. ft. by 27 cu. ft./cu. yd. to get cubic yards;
<br /> �:�� cu. ft. — 27 =�cu. yd. ii
<br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; �� cu. yu. n 1.�} I
<br /> ton/cu. y d. = 3� tons.
<br /> ;
<br /> _..�.,�.._..__ __...�
<br /> ____ �__;.�...,_ ___ ,_.� ._ ,
<br /> ...._.�_..�:;.Y:...���.,..
<br /> F. ABSOP�l'TION WIDTH �„�44.,www si�.,:.,��.,��� �.�; ,
<br /> 1. Percolarion rate in top 12 inches of soil is"�G' � mpi �n�.��,<.,.�� �;,;,,,�,,,, �,,;<,,, ,,,,�,,,,,�
<br /> Texture ^�'�/�I�1 1 ) Nt�nuw�,cr Irwh SWI Tc..iws Fw.isr sc: ��..::.w N:,;:a
<br /> �.��. .� /-- '��,$ �r�j ! (��wi ,.,;...��,..�c �_ .,ww�e�
<br /> �_ , __r... ..:-...,.......... �
<br /> /�Q`7�� •�yL 5.�-��"] Fawc�u4..�o� c�:,�. s.�a �'�. ':w i•
<br /> UJ w± 5..,..r t ...: .. ,iU ��
<br /> 2. Select allowable soil loading rate rom table; ' ����� �,�u � ,�- � �
<br /> e w�� s.w,� .wi u . , �z
<br /> Q:�� �pd/ft� �e� � � .__ �
<br /> --j�"`s� =S�i .��.,_; ,,G:f. I::,.� 'd'. i;
<br /> �6 tu o`o� C�..r t.....0 �;�.. �- --
<br /> .�- '
<br /> GO W I.:J CI.Y v t -��
<br /> 3. Calculate ddsorption width ratio by dividing rock layer s,oW«�,.�,�.o c�.., �: .: �, ;;
<br /> loading rate of 1.20 �pd/ft2 by allo�vable soil loading rate; � �
<br /> 1.20 gpd/ftz;-a�� gpd/ftz = ?, �6 ;
<br /> ;
<br /> �
<br /> �. Multiply adsorption width ratio by rock layer width to get ;
<br /> required adsorption width; �
<br /> 2.yG X _/o ft = Zy � ;
<br />
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