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PUMP ��I.CCTION PR4�GEDURE <br /> ,� :�. Uctrrmine pump capacity: <br /> Gravity Distribution <br /> 1. Mu�ui�um suggested is 20 gpm <br /> 2. Ma�.unum subbested is�15 bpn� <br /> Pressur� Distibution <br /> 3. a. 5clect ilun�b�r of perforated laterals Perforatir,n t)ischar�;cs in G!'M <br /> b. Srlect perforatioil spaCin�; = Eeet. tiead ('��rluralu,n diarneier <br /> c. �ubtract 2 ft. from t}le rock la}�t�r lenbtll. tert i�«t,t�} <br /> a.,.��.,,r��r���,-2 ft. = feet. ' �3z �ta <br /> d. Urtcrmine the nurnber of�ace� betwcen perforations. 1.0� u.56 u�a <br /> Lerl�;th peiF. �paciiig = ft.T ft. _ � spaces � 1.5 u.t.�y u.��u <br /> 2.Ub t�.ttU I.U-3 <br /> t�. _spau; + 1 =__ perforations/lateral --- <br /> f. hlultiply perforations per lateral by number of lati�rals to �Use 1.o t..,���inl;�� 'r�,�m��. <br /> b Use 2.0 trui ior.,,�.;slun�;elw. <br /> ��t tutal nucnber of perforations. Arr� x F4�s a r� = perforations. <br /> �;. 1�' � �E,�„ ,,.: ---bPm' , <br /> SELGCTED PUMP CAPACIT'Y��gpm <br /> , , <br /> �. '� �y �Jl�ICCAUR�'llt 7�':, <br /> l3. Uetcrciiine head reyuiren�ents: �:�``� ____ <br /> � ,��� i�-J.'�J.-�•»,� <br /> 1. l:l�•vation difference between ump and puint of dischargc. - <br /> � feet ��Tuta }>ipe]an��,tt. <br /> ?. lt pumpul�; to a prrssure distribu:ion system,Eive fret for pressure <br /> r���uir��i at iiia�lifuld if gravity �ystem, zero. """`` <br /> � S feet �,i�� � ,i,:4�r,<:� :;�ttwr�,ti� v <br /> . pipr T <br /> �. 1'CiltlVll lUSS ------ `� <br /> a. L'nter friction loss table with bpm and pipe diaineter. a ..����-�-�-�� � <br /> -------------..__�_ ......-----•----- <br /> (:��ad friction loss in feet per 100 feet from table(f�-14). W�Y> -- <br /> 1�.L. =3 1_�ft./lU0 ft of pipe ' <br /> l�. l->etcrmir��� tot�il pipe l��nbth from pump to discharbe � �T'1Ctic,It I..i��r=��E tii �'1d5tiC Y�tpe <br /> ruiilt. I�;tiinate by adding 25 percent to pipe len�th for fittin� r.i:,;3,ina1 <br /> lus,,or use a fittulg loss chart (1=-15 feet). �,.,�e dia. <br /> f:quivalent pipe length - 1.25 times pipe lenbth = Flow Itate �... ,,,, <br /> ��x 125 = �ST feet gprn � ' ` � <br /> c. Calculate total friction loss by multiplying <br /> triction I;�ss in ft/lU0 ft by equivalent pipe leitgtli. 5� 'ZO 2.�;:' t�.73 U.11 <br /> T�tal frictiui�loss = ���_x ,3 >� +100= 3�u feet 'S 3.;:� I.11 O.In <br /> }..h5 0�3 <br /> -�. T�tal head required is the suin of elevation difference, 35 �.<i� "�Oo U.3>> <br /> sj��c�cial tlead requirements,and total friction loss. �U E.rl '.c-i 0.3':� <br /> � + 5 + 3 � — �,��� `" 7l.iJ� S_?.ti_ (1.4'3 <br /> S �.riU�,� 1::i•i„ �.,��9 1 O.Sti <br /> (1) (2) (3c) 5:i '_;l.T� 0.7u <br /> � 60 `�.tiU t).b' <br /> �`i G .iri 0.�� <br /> 7'OTAL tiEAU � � feet %U :'�� l.U�� <br /> i <br /> G Punip s�lection <br /> i 1. A ptimp must be selected to deliver ��t least <br /> _SJ bpin (St�:p A) �vith at least � feet of totzl head (Step B). <br /> L___- <br />