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. • END PE�iFORATIUN OF A PEiiF'URATEO LATERAI. <br /> ��[LRE DISTRIFSUTtOI�J SYS i Et�1 <br /> /-c�u� c..�K <br /> • r�......—i � �',i,�.1: <br /> t t�000n �ty�;, • <br /> 1. Select number of perforated laterals � c��:--.------?^-:�� <br /> • � Lr/�r c�/ Gao�et+lia FoWlc 1•`�. <br /> • lsorny Send Lo1'�r 'in-n inrM o� �rr o� ��o.t♦ <br /> }��wTtn��O win pM.n�, <br /> 2. Select perforation spacing = ? feet ��,j,:,r,-�;,�u;�'- ,�—�.�����.� DrIII�J Ilerlrea�..;- <br /> ' y7 . . ... .� .�{nie C�p Mor Top <br /> ' �PLoin`Fitld Aockpl,\ ,.;y�j��jy�! Pocl1Le�a• E�p� <br /> 3. Since perforations should not be placed closer, tl�an 1 ft. to �-��---� � <br /> —PnIpr011�rr LnSu��d el <br /> t11e edge of the rock layer (see diagram), subtract 2 ft. from ��.a� �.,a �eYn B°"°'^ .` `°„'°' <br /> the rock layer length. �- <br /> �Moi So11 �.e�r.rly Sealt{b <br /> P.Iw��iuclo0 Sr�d Lov�• <br /> .���i <br /> R�xk laycr lcngth - 2 f t. = �� ���� f eet <br /> TA�LE Or PCI:POTtATiON QiSCI inRCL"•S 1N GPM <br /> 4. Determine the number of spaces between perforations. ��,a I'crfor�:ion diamctcr(inthes) <br /> Divide the length above by perforation spacing and round <br /> down to nearest whole number. '�" ��' <br /> ].Oa 0.56 0.74 <br /> Length perf. spacing = ,�'''_, ft. +_,�'_ ft. = 1 '1 spaces z�b �gn °'� <br /> (#3� (#2) :.5 0.89 1.17 <br /> 5. Number of erforations is e ual to one lus tlle number of 3.0 o.sa �.ze <br /> P �l P a.o i.�s i.�� <br /> perforation spaces . 5.� i.z6 t.as <br /> aUse 1.0 foot of t. i (or rrsidcntial ay�tem�. <br /> �spaces + 1 = �_perforatioi�s per lateral E�Usc 2.0(cet of head for othcr establishme,i�s <br /> 6. Multiply perfviations pec lateral by number of laterals to <br /> get total number of perforations. �" <br /> Table 2 <br /> �� x -�—� - � perforations �lozimumalbwRbienumborofqunlcrinchper(urvliun�per <br /> laleral a peris/latcral latcral ta uanntce<10'k Ui�ch��ye rnrialion <br /> ►°��''�^^�•�'^� 1.25 inch 1.5 inch 2.0 inch <br /> <<<.�� <br /> 7. Determine required flow rate by multiplying Z.5 14 ]8 2� <br /> number of perforations by flow per perforation 3.0 13 �7 2G <br /> 3.3 12 16 25 <br /> 4.0 1 l l 5 23 <br /> � 5.0 i0 ]4 22 <br /> C�rs x �r = �" C� gpm. <br /> 8. If laterals are connected to header pipe as sl�own on upper � ��` ���� M�`� <br /> example,select minimum required lateral diameter from �. <br /> table 2; enter table with perforation spacing and number � <br /> of perforations per lateral. Select minimui» �-�iameter for �; ,. . <br /> perforated lateral = inches ,,�.�'� ��'u- I <br /> .✓-�, <br /> 9. If perforated lateral system is attach�d to manifold pipe near <br /> the center, as in lower example, perforated lateral length and `""'�-t'��'=�=="=-'"' <br /> number of erforations er lateral will be a roximatel one """'"'"'"' <br /> P P FP Y �_��.�.. <br /> .. r.._,�.�, r �� <br /> half of that in # 6. Using these values, select minimum ���� �-- � <br /> �,�:- <br /> diameter for perforated lateral from table 2 -��-�--� <br /> perforated lateral = �/-� inches ,� � � ''�''� <br /> r- � � <br /> �.... � /� <br /> �a•�"�,,��'"�� ��.. <br /> • � ,�� <br /> � <br />