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� = MOUtVD DESIGN K'ORKSHE�`T' <br /> (For Flows up to 1200 gpd) <br /> r�. FLOW r IiR�imricd Scw�ae�luavs m(iu1l�Kic pv Jwy � <br /> (�r��) I <br /> Estimated _�c� gpd (see pages D-7 or I-3, 4, 5) �m,x, <br /> or measured — gpd x 1.5 = -- ,��d;�„„� T,'"�'�rY�'rr��" T��� I <br /> , ' ; ?00 225 1Rp I <br /> B. SEPTIC TANK LIQUID VOLUMES 3 4so �c� zin «� <br /> �� - /nv O gallons (see pages C-3 or C-5) ° ���' �'s z�� ;'� <br /> s �so aso zvo ''�' <br /> G 9t%1 525 J12 r�r.�. <br /> � l Ot0 G(l() 370 ��� <br /> A i2c10 Gi5 A(ui �d��x <br /> C. SOILS (refer to site evaluation) <br /> � �,� —� � \aylic TI.\C�p�a'IIYx In KYI{.M+ <br /> 1. Depth to restricting layer = ?�%, ,<� �,�^ inches � __ <br /> \omM.n( Mmm�um LiyuiJ I.pud cq.a��ry�.iih <br /> 2. Depth of percolation tests = ► �' , inclles �k�,�'^'^t �,�.,-;�y i.�ti°��a"�,�..i <br /> 3. Percolation rate �I . I m i 2�~��� '� "'s <br /> � )«a �c�x� ixn <br /> , p ♦Mr �y�� 1?_w <br /> 4. Land slope � lo ,,�,xo b,�, ,,,x, <br /> mci9 •••••• <br /> D. ROCK LAY�R DIMENSIONS -- <br /> 1. Multiply flow rate by 0.83 ta obtain rec�uirec� area of rock <br /> layer: Daily Flow x 0.83 = <br /> �-C D gpd x 0.83 sq. f t./gpd = '-��-� 'J sq. f t. -+ ��� '� , ' '' ) <br /> 2. Select width of rock layer (10 feet or less) = � c� ft. <br /> 3. Length of rock layer = Area + Widt}� _ <br /> ��-t � sc�. f t. -�- l C, f t. _ �� f t. Rc�ck Bed <br /> _ ���f�-�:�f�f�f�-���:�-�-��-f:f T <br /> :'rtii: lr:ft:: ':f::tir:�� 1'Vidlh 510 ft. <br /> .'�:f:r•r'%:i'•:r: �'r:�.;:'i:f� <br /> �,f���:�f���•tif�. :�.•...�..�..�. <br /> E. ROCK VOLLTME �----�Lcngth�� �--+ <br /> 1. Multiply rock area by rock depth ta get cubic feet of rock; <br /> ��-�� sq. f t. x �.c, �- f t. - � cu. f t. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> ��-� cu. f t. +27 = � 1 cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> �.t ► cu. yd. x 1.4 ton/cu. yd. _ '- tons. <br /> F. ADSORPTION WIDTH '->_"`� '_'"`, " , <br /> 1. Percolation rate in top 12 inches of soil is '�. ' mpi �hu�rplion Width SizlnK�ble <br /> 1'ercnlaticx�Re�c Gi�kxn RiUo o! <br /> 2. Select allowable soil loading rate from table on page E-; ��M;�„��s� sa��r�R��� ,�.�.Y,�� ��„;,�.,;a�h <br /> Inch 1MVI) �yusre f� l0 11�Kk L.+�yn <br /> � `'' gp�/f tZ WK��� <br /> 3. Calculate adsorption width ratio by dividing rock layer F��.�.<<�,.���• c«�s�,e .._- _... <br /> o.i�os so�� i.zo �.00 <br /> loading rate of 1.20 gpd/ft�by allowable soil loading rate; o.►��s•• F�M sy�a•• o.c�o �.�p <br /> 610 13 Snndy Lruun 0.��1 1.52 <br /> 1.20 gpd/f tz+ . �a f gpa/ftz- :� . �,_� �b���u �.m o.eo z.��, <br /> 31 l0 41 Sili Lo�m O.SO 7.40 <br /> Check this value on pageE-16. «�o� c�.�-�„ o.s z.�� <br /> �;� �o izn �:,y o.z� s.�z� <br /> 4. Multiply adsorption width ratio by rock layer width to get s��o;;;A^ c�■r ----. ---.. <br /> required adsorption width; <br /> � .:.-� x I c, f t = .:� �-.�� f t � <br /> I <br />