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' ' F-17 <br /> Y <br /> ��.�- PII?�fP SELECTION PROCEDt7RE <br /> E!D PERFORATION OF 4 P£RFORATED �7E�a�L <br /> A Determine pump capadty: <br /> w�� <br /> Gravity Distribution <br /> Tep.dl <br /> l. Minimum suggested is 600 gallons per hour(70 gpm) to stay ahead of = ,: � <br /> water use rate. :-.�"'�s°"°�^*�. ;�~`..�"..`m.`c>a,- <br /> a...��„. �..... <br /> .,.<....,�; <br /> 2. Maximum suggested for delivery to a drop box of a home system is 2,700 ,. . ~�b•��a��•.>.m.�•�� <br /> ht�CAO I�or Te1 <br /> gallons per hour(45 gpm)to prevent build-up of pressure in drop box. �.,•R�. : -„ ��,,, ,t,. «n <br /> �?peA/l�ld •! Roca L►�w <br /> Pressnre Distibution ����..,sa,,.,a,� `"'"'�`"""�"`�� <br /> �.�b.,w��..., <br /> 3.a. Select number of perforated laterals � <br /> b. Select rforation s cin feet °"��° ^����� <br /> Pe Pa g= �,r.�,,.��.,., <br /> c. Subtract 2 ft from the roc]c layer length. <br /> ���-2 ft._ '. !- feet <br /> d. Determule the number of spaces betiveen perforations. <br /> I.ength perf.spacing= (�c: ft.+ � ft._ �� spaces Required Perfonbon Discha. e <br /> e. �� spaces+ 1 = �'�> perforationsllatesal m�iions pe.r min�ce(gpa,� <br /> f. Muldply perforations per latera]b�numberr�of]aterals to ���a��,n 'A�a e �2 m�� i �� <br /> get total number of perforations. i��� x �„ ��= C,S perforations. �f�U <br /> g' � X�aQ+=��gpm. <br /> 1.Oa 0.56 0.74 � <br /> SELEC'T'�.�D PUMP CAPACITY ?�'i gpm 2.�b �.g0 1.�4 ' <br /> B.Determine head requirements: a.Use for single famiIy homes <br /> 1. Elevation difference between pump and point of discharge. b.Use for all other applicahons <br /> / f feet <br /> �� , 2. If pumping to a pressure distribution rystem,five feet for pressure <br /> requirec�t manifold if gravity system,zero. <br /> � feet <br /> ' 3. Fricdon loss <br /> a. Enter friction]oss table with gpm and pipe diameter. Pipc L,e�g�h <br /> Read friction loss in feet per 100 feet trom table. ` Poinc of Dischargc <br /> F.L= �.�. ft./100 ft of pipe �.,;-? <br /> b. Determine total pipe length from pump to discharge Elcvarion Diffcrcnce <br /> poinL Add?5 percent to pipe length for fithng �p � q� <br /> loss,or use a fitting]oss chart. Equivalent pipe <br /> length-1.25 times�ipe length= F-18b <br /> �x 1.25 = � ) � feet <br /> c. Calculate total friction]oss by multiplying 1.S��h��2.0 inch 3.0 inch <br /> gpm �ioo a�r�a� <br /> friction loss in ft/100 ft by equivalent pipe length. <br /> Total friction loss= _ � .�.- x � 1 ;; +100=_��feet l0 0.69 0.20 <br /> ,� 12 0.96 0.28 <br /> 4. Total head required is the sum of elevation difference, 14 1.28 0.38 <br /> special head requirements,and tota] friction]oss. 16 1.63 0.48 <br /> 18 2.03 0.60 <br /> � � + { + G 20 2.47 0.73 0.11 <br /> 25 3.73 i.11 0.16 <br /> (1) (2) (3�) 30 5.23 1S5 0.23 <br /> 35 7.90 2.06 030 <br /> TOTAL HEAD �a feet - -� 11.07 2.64 0.39 <br /> 45 14.73 3.28 0.48 <br /> 50 3.99 0.58 <br /> C Pum selection ss a.�6 0.�0 <br /> P �o s.�o o.s2 <br /> �;;;% 1. A pump must be selected to deliver at least <br /> � _.�gpm (Step A) with at least ?�� feet of total head (Step B). <br />