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, PRESSURE DISTRIBUTION SYSTEM Geotextile fabric <br /> 1. Select number of perforated Daterals 3 ���:,o:��;; �,.__;��,� 12" <br /> i v�:,.,,o. SNaCeci wl.i� I f'-- <br /> 2. Select perforation spacing = 3 ' o ft s''of r°`k <br /> Perf Sizing 3/16"- 1/4" <br /> 3. Since perforations should not be placed closer than 1 foot to Perf Spacing 1.5�-s� <br /> the edge of the rock layer (see diagram),subtract 2 feet from <br /> the rock layer length. E-4: Maximum ollowable number of 1/4-inch periorotion <br /> 7 � ? per lateral to guarantee<10%discharge variation <br /> Rock ayer eng —2 ft — � J ft <br /> perforation <br /> 4. Determine the number of spaces between perforations. spacing <br /> Divide the length (3)by perforation spacing(2) and r un feet 1 inch 1.25 inch 1.5 inch 2.0 inch <br /> wn to nearest whole number. <br /> 2.5 8 14 18 28 <br /> Perforation spacing = '�3 ft=�ft= a�spaces 3.0 8 13 17 26 <br /> 5. Number of perforations is equal to one plus the number of 3'3 � 12 �6 25 <br /> perforation spaces(4). Check figure E-4 to assure the number of 4'0 > i> �5 23 <br /> perforations per lateral guarantees <10% discharge variation. 5,0 6 10 1q 22 <br /> a�_spaces + 1 = �.� perforations/lateral E-6: Perforotfon Discharge in gpm <br /> 6. A. Total number of perforations = perforations per lateral (5) perforation diameter <br /> times number of laterals (1) head inches <br /> a� perfs/lat x�_lat=�perforations (feet) 3/16 7/32 1/4 <br /> 1.Oa 0.42 0.56 0.74 <br /> B. Calculate the square footage per perforation. <br /> Should be 6-10 sqft/perf. Does not apply to at-grades. 2•0b 0.59 0.80 1.04 <br /> Rock bed area = rock width (ft) x rock length (ft) 5.0 0.94 1.26 1.65 <br /> �� ft X�ft= �SC� Sqft ° Use 1.0 foot for single-family homes. <br /> Square foot per perforation = Rock bed area =number of perfs (6) b Use 2.0 feet for an hin else. <br /> r]Sv sqft+�_perfs = c�•c� sqft/perf <br /> MANIFOID LOCATED 4T ENO OF pqE55URE DISTRIBUTION SYSTE <br /> 7. Determule required flow rate by multiplying the total number of <br /> perforations (6A) by flow per perforation(see figure E-6) W,,,a, <br /> 7S perfs x " Slo �l/3 erfs��� Z ~ <br /> gpm P -�_gpm .,.��. <br /> 8. If laterals are connected to header pipe as shown on upper � <br /> example, to select minunum required lateral diameter;enter ,�,,�«°`"`� �'"�u <br /> figure E-4 with perforation spacing (2) and number of perforations \�`"`M d <br /> per lateral (5) Select minimum diameter for <br /> perforated lateral- ��eS, �.W. a�C11lOMTED►IPC L�TEn�LS roa <br /> — PR[33WIE msTA�surion w rou�o <br /> [nau[D RurK�r[ <br /> 9. If perforated lateral system is attached to manifold pipe near �,„�,,, <br /> the center, lower diagram,perforated lateral length (3) and �"� ���`"'` �"��� . �""'°"�'�y�� <br /> Yw f�qo <br /> number of perforations per lateral (5)will be approximately one n.�..,o,��,,,,,�,„ <br /> .,.,..�.,.� <br /> a o that in step 8. Using these values, select minimum 'o\ s- <br /> diameter for perforated lateral= �� 1 Z inches. � ���aT""''� <br /> `` "°`.. e" ���.� ' <br /> d r����o� �^^"" . . <br /> \ ���M <br /> :� <br /> I hereby certify that I have completed this work in accordance with applicable ordinances, rules and laws. <br /> � �' � (signature) �"1'� (license#) �6 �oZ45-OZ (date) <br />