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ONS�T! � <br /> SlWAi6C '�1 Job#� <br /> TRE/�TMENT r_,����;_ <br /> PROGiRAN! <br /> University of Minnesota Mound Design Worksheet <br /> Greaterthan 1°/.Slopes <br /> A FLOW <br /> Estimated 600 9Pd(see 6gure A-1) <br /> or measured x 1.5(safety factor)= 0 gpd <br /> B. SEPTIC TANK LIQUID VOLUMfS <br /> Septic tank capaaty 2000 gailons(see figure G1) <br /> Number of tankslcompartments 0 <br /> Effluent Flter (yes/no) yes <br /> C-1 Septic Tank Capacity in Gallons <br /> Number of Minimum Capacity with Capacity with <br /> Bedrooms Capacity Garb.Disp. Disp.and Lift <br /> 2 or less 750 1125 1500 <br /> 3 or 4 1000 1500 2000 <br /> 5 or6 1500 2250 3000 <br /> 7,8 or 9 2000 3000 4000 <br /> C. SOILS(Sife evaluafion data) <br /> 1. Depth to reshicting layer- 1.8 feet <br /> 2. Depth of percolation tests= 12 inches <br /> 3. Texture loam <br /> 4. Soil loading rate(see Figure D-33) p.gp gpd/ft <br /> Percolation rate 12 MPI <br /> 5. %L�d Slope 12.0 % <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply average design flow(A)by 0.83 to obtain required�ea of rodc layer:Item A x 0.83= <br /> 600 gpd x 0.83 ft/gpd= 500 ft2 <br /> 2. Detertnine rock layer width =0.83 ft`/gpd x Linear Loading Rake(LLR)(see LLR chart <br /> 0.83 ft�/gpd x 12.00 = 10.0 ft <br /> LLR Chart <br /> Perk Rate LLR <br /> <120 MPI <=12 <br /> >=120 MPI <=6 <br /> 3. Length of ra:k layer=�ea divided by width= <br /> 500.0 ft/ 10.0 feet= 50.0 ft <br /> E. ROCK VOLUME <br /> 1. Multiply rodc area by ra�c d�th to get cubic feet of rock <br /> 500.0 X 1.0 ft= 500.0 ft3 <br /> 2. Divide ft�by 27 ft3/yd3 to get cubic yards <br /> 500.0 ft3 / 27 = 18.5 yd3 <br /> 3. Mul6ply cubic yards by 1.4 to get weight of rodc in tais; <br /> 18.5 yd3 X 1.4 ton/yd3 = 25.9 t�s <br /> Page 1 of 5 <br />