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. END PERFORATION OF A PERFORATED LATERAL <br /> PRESSURE DISTRIBUTION SYSTEM <br /> l-c.�. ca�K <br /> Topsoll � <br /> 1. Select number of perforated laterals � , .L--. <br /> �..�. �LoYM of G�ot�atll• Fob�lc (w tau- <br /> � Loomy Sand Lny�r ' Inc�Icyef ol hay w �tiow cover<d <br /> .� :. wltn reC rosin paper) <br /> 2. Select perforation spacing = 2�S feeE �, ,a P�.�o:o„«� o„���� �o,��a��e��, <br /> � �.�Inro GOD �ar Top <br /> � <br /> y��i Plm , -At Lmst 12�io Edq• <br /> 3. Since perforations should not be placed closer than 1 ft. to �Oroln Fleld Rock -,�" ol Ra�x �oY.. <br /> -Perlaallona Lucoted ol <br /> the edge of the rock layer (see diagram), subtract 2 ft. from ���a� ��a �ar« B°"°^' °' �°'°.°' <br /> the rock layer length. ` <br /> Cv3 �� oria�,ai smi P.00.ny s�onrea <br /> � Belof� Ploci�q Sand Laye� <br /> Rocktayerlength - 2' ft. - � feet <br /> Tr1BLE OF PLRFORATION DISCHARCLS IN GP!�l <br /> 4. Determine the number of spaces between perforations. x�aa Perforation diameter(inches) <br /> Divide the length above by perforation spacing and round <br /> down to nearest whole number. '�n '�� <br /> Cc' `�� 1.Oa 0.56 0.74 <br /> Length perf. spacing =� ft. -� ft. =�_ s aces l.s 0.69 0.90 <br /> p 2.Ob 0.80 1.44 <br /> �#3� �#?� 2.5 0.89 1.17 <br /> 5. Number of erforations is e ual to one lus the number of 3.0 o.9s i.zs <br /> P 9 P a.o l.�s �.�� <br /> perforation spaces . s.o �.26 1.� <br /> -� , � -- <br /> �~� aUse 1.0 foot of head for residential systems. <br /> spaces + 1 = �_ J perforaEions per lateral blise 2.0 fcet of head for otilerestablishments <br /> 6. Multiply perforations per lateral by nuinber of laterals to <br /> get total number of perforations. <br /> � -�- Table 2 <br /> � ;: <br /> r '.Nasimum allow�ble number o!qualcr inch perforalions per � <br /> lateral s X perfs/lateral �"'` perforations latcral to guanntce�1056 Discharge vui�lion q <br /> a�°"����'�"'"� 1.25 inch I 1.5 inch I 2.0 inch <br /> 7. Determine required flow rate by multiplying 2.5 14 � 18 � 28 � <br /> number of perforations by flow per perforation 3.0 13 ; 17 26 1 <br /> 3.3 12 I 16 25 � <br /> �� •7�"� ;..;"�. 4.0 11 � 15 23 <br /> �,a r 5.0 10 � 14 22 <br /> pafs X gpm/perf �gPm. <br /> � in� co• w or atsswc asra.wn�w srs*cr <br /> 8. If laterals are connected to header pipe as shown on upper <br /> example, select minimum required lateral diameter from �.. <br /> table 2; enter table with perforation spacing and number �_....--�-'""�� � <br /> of perforations per lateral. Select minimum diameter for �.--''`� <br /> �_j. <br /> perforated lateral = 2 inches �,,,.-��'` �=�=- <br /> �/ <br /> ' 9. If perforated lateral system is attached to manifold pipe near <br /> the center, as in lower example, perforated lateral length and `•'°"'�R_�,��="�"' <br /> number of perforations per lateral will be approximately one c�`�"�`"""` ,; <br /> half of that in # 6. Using these values, select minimum �-��=�� " �1°""'�^�� <br /> diameter for perforated lateral from table 2 ��w�-�~-- �. <br /> perforated lateral = inches l- �M �,. ""�'�� <br /> � .• .yr <br /> �y-/;%�•,�r+"� �.�...._... <br />