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Ferndale Road North
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395 Ferndale Road North - 36-118-23-41-0001
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Last modified
8/22/2023 5:03:49 PM
Creation date
8/10/2016 2:38:48 PM
Metadata
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Template:
x Address Old
House Number
395
Street Name
Ferndale
Street Type
Road
Street Direction
North
Address
395 Ferndale Road North
Document Type
Septic
PIN
3611823410001
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MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> , 7 <br /> A. FLOW Estimuee s�.�at�Flo�in c,u«,s pa�.r esna) <br /> Estimated �_gpd N""� �ry�t �tyy�tt 1y�in �ry�rv <br /> or measured - x 1.5 = -' gpd• a��� <br /> s �oo xas �eo �. <br /> 3 130 )00 218 •r <br /> B. SII'TIC TANK I.IQUID VOLLTMES ' b°° "s zs� ,� <br /> s �so �so z�. � <br /> 6 soo su »z � <br /> I_ , �.SG � 1 -�o c�o gallons � iaso boo »o •,'� <br /> a �zoo s�s ,oa <br /> �� <br /> C. SOIIS (refer to site evaluation) �`'�'�� '' <br /> a�,' ;,.� ; �� N�ee � ,..� <br /> ''��.� `�"�'.,�a <br /> 1. Depth to restricting layer= '�30"' �inches "r °.,`• <br /> sed�oom. c..+ry � <br /> 2. Depth of percoladon tests = I a ' ' inches `'+"'' `�"" <br /> 3. Percolation rate 5�� mpi �i a�` �'.o�oo i'.'s o <br /> 4. Land Slope .,{ % �a i zoo s ooSOo <br /> �.9 se.�s�.c.� ��is� <br /> D. ROCK LAYER DIlvfFNSIONS <br /> 1. Multiply flow rate by 0.83 to obta.in required area of rocic <br /> layer: A x 0.83 = <br /> �so , gpd x 0.83 sq. R./gpd = � _� sq. ft. <br /> 2. Select width of rock layer (10 feet or less) _ ,�, ft. <br /> 3. Length of rock layer = azea+width = Rocic Bed <br /> �a a, .Sq. 1 C. "'�' L�1 t. = �2� 1 t. ��1 f'�,�f�fti�,���ti�ti f�fti�1 fti f�fti fti <br /> 1.�•ti•y1•�•�•ti•�1•ti•1•tiN•ti•1•1 <br /> r.�•�.r•r•r.�•�•� �.r•r•r•f.r.r. idth S10 ft. <br /> �.�•ti•ti.ti•ti.�,•ti•�•ti•ti•ti•�•�•�•ti•ti <br /> r•f•r•�•r•r•�•�•� r•r•r•r•r•r•r• <br /> �.ti•1•�•1•�K•�•1•�•1•�•�•ti�1•1•1 <br /> .r.t.1.I./.f.r.f.r.r.�.�.r.�.r.r. <br /> E. ROCK VOLUME ~- �'�' -� <br /> 1. Multiply rock azea by rock depth to get cubic feet of rock; <br /> ,��2 sq. ft. x .��s ft. = c� cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft:/cu. yd. to get cubic yards; <br /> �cu.ft. +27=�.�cu. yd. <br /> 3. Multiply cutiic yazds by 1.4 to get weight of rock in tons; <br /> �cu. yd. x 1.4 ton/cu. yd. _ ,� tons. <br /> F. ADSORPTION WIDTH ��-ra,� _c�v� � ,�, tla,mew s�„ Lbk <br /> 1. Percolation rate in top 12 inches of soil is 5,o mpi r�,ro,,tl�,�.a �°� `~� <br /> M�„�,u,pR�, Soil Texture �,� �„� <br /> (mpD '- •'�, <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 oarse Sand �.2o i.00 <br /> d/ft� 0.] to5 Sand 1.20 1.00 <br /> ,y-� $p 0.1 to 5 Fine Sand" �•� z•� <br /> 6 to 15 ndy Loam 0.79 1�2 <br /> 3. Calculate adso tion width ratio b dividin rock la er 16 co�o �,o�m o.bo z.00 <br /> rp y g Y ai co as s►�c t,�m oso z.ao <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; 61 eo 21� Cla��t.,o�, o�a s.00 <br /> 1.20 gPd/�y ,��=gpd/ft� _ �,l�';� Slower than 120 Cla - - <br /> "Soil Tavie�507C w maer d fine or vey fine sand <br /> 4. Multiply adsorpdon width ratio by rock layer width to get <br /> required adsorption width; <br /> �2,x�_ft=�_ft <br />
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