|
,. . ..
<br /> , ,:r ' . .. �;,.
<br /> � ' �;� ,,. � � MOUND DESIGN;WORKSHEET -
<br /> , • . ' � ,,t � ,
<br /> ;;; (For Flows up to 1200 gpd) ,
<br /> - .. . � . 7,�,j. . .
<br /> A. �..�W . �r° ; , � , y �, � - Estimated Sew�e Flowt ia Gallooi per day
<br /> Estimated�Q, "� h ` _. 3a t' d
<br /> gPd" • '° ' :
<br /> ;� `, F ` ;,,� f �i. 4 f� �. �.r i N� 7)'p°� 7�p°II 'I�pe� 7Ype
<br /> or measured �x�1.5 � .�ppd f„ ;�, � �r` , , , rv
<br /> �,",� � ,a , ;..
<br /> � � ��i����°� y-,,��y��� t� . •� � �r.ti,:� �� � .����� '�� � �2 300 225 180
<br /> �`��_�, � ��3`� �aso �oo ���iia a�
<br /> B. SEPTTC TANK�,L;IQUID.VOLUMES,.�:� ' . ; �.� � „s ��
<br /> Z'- /2 $� �_,t�a.<. ;„, .., � ,, , s aso 29a "'b'a
<br /> �� gallons k� , ,' , r;. ..x ,` 6 szs �3z "
<br /> ' ,` ' � ioso � � rya i.
<br /> ,,;'da+,� s,,4 , e� ' 8 120U 673 JOB Ila
<br /> :<� ,.� . , ' r , III
<br /> C. SOILS (refer to site.evaluation) � " °°'�
<br /> ► J
<br /> <
<br /> 1 ,: Depth to zestncting:layer=;��'inches!`�f�<I• ..�feet: - �w+���ca�,n�,cw��
<br /> �; � .
<br /> 2 .�Depth of�percolation tests�= '�I Z ,lllC�'lE'S ' � � Number of •Minimum Liduid l�quid cap�city wiih
<br /> �o,., ,a , x;.,,,, . '• . , �. Bedroom� Capaciry Suba6e dispos�l
<br /> 3. ` Texture � �,a.�►r � Percolation rate m i
<br /> �-�'=� P
<br /> 4. Land slope: . .>,,T ' % . � �3 0�o' ;oso°o ���s
<br /> ;;:;a�,., s o�6 isao �
<br /> . . �.a o�9 z000 3000
<br /> D. R K LAYERI,DIMENSI NS : . .s, .
<br /> 1. Mulhply,flow;rate by,0 83'to obtain required area;of rock layer: A x 0.83 =
<br /> � �q: ���,„»�j� — ,.,�d'z 0:83 sq:ft.%gpd =%�,a:'sq:ft. ' � <
<br /> 2. Select w'idth of;rock layer'(max..10' if�<120'mpi�:max'5') = 0 ft.
<br /> 3. Length of;rock'layer"= area+width= :. ;: ,�^',.. ".' �
<br /> �.a.�.a tt: . .. � :..
<br /> y ` a s"'t+fd '4�.� � , �4
<br /> �z�sq ft:+ /o .ft.�= G ZL ft. ��a��b�;�.;P�C�e P �
<br /> +' o•�q. a.p.o.......op.a �
<br /> � ,p:
<br /> - Width /o ft °
<br /> �.; � . , <120mpi <10' Length Gy� ft
<br /> E. ROCK�VOLUME;.` , >120mpi <5' .
<br /> L Mulhply'rock area by'sock depth to get cubic feet of rock;�sq. ft. x .0 S �
<br /> ,,.: r �.
<br /> �;. ft. _�cu. ft.
<br /> 2. Divide cu �ft: by 27 cu.'ft./cu, yd. to get cubic yards;
<br /> �.�.cu. ft. +27=a,�cu.�yd.
<br /> 3. Multiply_�cubic yards by 1.4 to get wei ht of rock in tons;�5 cu. yd. x 1.4
<br /> ;.;, ��
<br /> ton/cu. yd. _�tons. '
<br /> �.;,
<br /> ,'�1�,, '
<br /> ' F. ABSORPTION��WIDTH . , , wnw�tloo wiaw sm��. �
<br /> 1. L'ercolat�on rate;in top 12 inches of soil is 3 D TTLPl percolstion Raoe in ' GaUaos RatiodAborpoa� ;
<br /> Texture � l,ae�.•� �+���«P«���, soa T�x� ��.,� ,��,a R«t .
<br /> (MPq squue faa Laya Width
<br /> � Faater rhan 0.1 Coana Saod 1.20 ' I.00
<br /> 0.1 to S Sand 1.20 I.00
<br /> 2. Select allowable soil loading rate from table; , o.��os Foes.� o.�o z.00
<br /> 6 to IS S Lwm 0.79 1.32
<br /> , � O pnd/� 31 to 43 Silt Loam 0.0 �40
<br /> vr
<br /> 46 to 60 C1ay Low 0.45 3.67
<br /> 60�o I?0 Clay 0.24 5.00
<br /> 3. Calculate adsorption width ratio by dividing rock layer "°W°��"°''-o c�eY o.w h.00
<br /> loading rate of 1:20 gpd/ft2 by allow ble soil loading rate;
<br /> '1.20 gpd/ft2i • �6 gpd/ft� _
<br /> 4. Multiply adsorption width rario by rock layer width to get
<br /> required adsorption width;
<br /> ,.
<br /> zt Ch? x �O ft= �!2 ft
<br />
|