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1999-011799 - septic
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Deer Run Tr E
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2760 Deer Run Trail East - 04-117-23-13-0009
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Previous address/PID(250 Old Crystal Bay Rd S)
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1999-011799 - septic
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Last modified
8/22/2023 5:07:55 PM
Creation date
6/28/2016 1:07:15 PM
Metadata
Fields
Template:
x Address Old
House Number
2760
Street Name
Deer Run
Street Type
Trail
Street Direction
East
Address
2760 Deer Run Tr E
Document Type
Permits/Inspections
PIN
0411723130009
Supplemental fields
ProcessedPID
Updated
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vlound Desian Worksheet <br /> � <br /> A. Flow I <br /> Estimated at 600 gallons per day (�pd) for a four bedroom dwellina. i <br /> — , <br /> I <br /> ' B. Septic Tank Liquid Volumes <br /> ', � of septic tanks = ? capacity= 1000 aallon tanks <br /> Lift station capacity = 1000 Qallons <br /> � <br /> i <br /> ' C. Soils (refer to soils loQ and percolation data sheets that follow) �i <br /> 1. Depth to restrictinQ layer= 26" i <br /> 2. Depth of percolation tests = 12" ' <br /> 3. TeYture of soils are loam/clav loam, use a percolation rate of=�� mpi. � <br /> =� Land slope = 6°% maximum on the South east corner. overall 4°'0 ' <br /> , <br /> D. Rock Laver Dimensions � <br /> ' l. Multiply flow rate by .83 to obtain required area of rock layer: A x .8� = I <br /> ', <br /> ' 600 x .83 = 500 square feet ', <br /> ; <br /> ?. Rock bed width �vill be 10 feet i <br /> , 3. Len�h of rock layer is the square feet area i width = ' <br /> ; <br /> 500 / 10 = �0 lineal feet <br /> I i <br /> ! E. Rock Volume i <br /> � 1. Multiply the rock area by the rock depth to determine the cubic feet of rock: � <br /> I 500 Y 1 = 500 cubic feet i <br /> I, 2. Divide the cubic feet by 27 cu. Feet to determine the cubic yards: � <br /> � 500 / 27 = 18.22 cubic yards � <br /> � 3. Multiply the cubic yards by 1.4 to determine the weiaht of rock in tons: i <br /> ' 18.22 Y 1.4 = 26 tons of clean washed aaQreaate rock. ; <br /> i soxrrto�n�ni srzr:e-+a� <br /> I PERC SOQ. ' GPD I R'.-0 OF <br /> � F. Absorption Width a.�rF �.��-n,-xE j rEx �:,x�no.��r� <br /> '� IN��I . � SQ FT I T�_�tER R�-__ <br /> > 01 Course Sand I I.:O I :.�: <br /> ' 1. Percolation rate in the top 12" of soil is 45 mpi. °``°` ' ""° '-° ' '" <br /> I U.1 ro S I Fine Sand '� .U60 I _�=6 <br /> '� Te:cture is clay loam. (Actual perc rate of 17.5 mpi) h�°�5 ; s�,��� ' 0-9 ; __ <br /> 16 to 30 Loam � A.60 I = <br /> � 31 to 13 Sdt Loam .0.30 � =-7 <br /> I16 ro 60 ' Clav Lwm '� O.SS � =i- - <br /> � 2. Select allowable soil loading rate from Table. �o � ��� ; °=j I `� <br /> � 0.45 gallons per day per square foot of rock area. <��� ��,� �-� � ��� <br /> � 3. Calculate the absorption width ratio by dividing the rock layer loading rate oi 1_2 <br /> � gpolft2 by allowable soil loading rate: I <br /> 1.2 / 0.45 =2.67 <br /> 4. Multiply the absorption width ratio by the rock layer width to determine the <br /> required absorption width; <br /> , 2.67 x 10 = 27 feet � <br />
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