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1999-012065 - new septic
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2755 Deer Run Trail East - 04-117-23-13-0014
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1999-012065 - new septic
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Last modified
8/22/2023 5:08:10 PM
Creation date
6/28/2016 12:23:35 PM
Metadata
Fields
Template:
x Address Old
House Number
2755
Street Name
Deer Run
Street Type
Trail
Street Direction
East
Address
2755 Deer Run Tr E
Document Type
Septic
PIN
0411723130014
Supplemental fields
ProcessedPID
Updated
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Mound Desi n Worksheet <br /> A. Flow <br /> Estimated at 750 gallons per day(gpd) for a five bedroom dwelling. <br /> B. Septic Tank Liquid Volumes <br /> # of septic tanks=2 capacity= each, 1500 alg lons <br /> Lift station capacity= 1500 gallons <br /> C. Soils (refer to soils log and percolation data sheets that follow) <br /> 1. Depth to restricting layer=27" <br /> 2. Depth of percolation tests= 12" <br /> 3. Texture of soils are Clay loam with a percolation rate of 47 minutes per inch. <br /> 4. Land slo e= 3 to 4% max. <br /> D. Rock Layer Dimensions <br /> 1. Mulriply flow rate by .83 to obtain required area of rock layer: A x 0.83 = <br /> 750 x .0.83 =630 square feet <br /> 2. Rock bed width will be 10 feet <br /> 3. Length of rock layer is the square feet area/width= <br /> 630/ 10=631ineal feet <br /> , <br /> E. Rock Volume <br /> 1. Multiply the rock area by the rock depth to determine the cubic feet of rock: <br /> 630 x 1 =630 cubic feet <br /> 2. Divide the cubic feet by 27 cu. Feet to determine the cubic yards: <br /> 630/27= 24 cubic yards <br /> 3. Multiply the cubic yards by 1.4 to determine the weight of rock in tons: <br /> 24 x 1.4 =32 tons of clean washed a re ate rock. <br /> SO ON W� S G T LF <br /> F. Absorption Width �� SO�� P R �o°a�oN�� <br /> IN�[PI S FT TO LAYER WIDTH <br /> >.Ol Crnase Smd 1.20 1.00 <br /> 1. Percolarion rate in the to 12"of soil is 46 m i. 01°°5 � '.2° '.°° <br /> P P o.��5 Fme Sand .060 �.� <br /> Texture is cla loam. 6�'S �`'�-�'" °.'9 '.32 <br /> Y 16 c�3o t�„ o.bo z.o <br /> 31 to 45 Silt L.oam .0.50 2.40 <br /> 46 to 60 Cla Lo�n 0.45 2.67 <br /> 2. Select allowable soil loading rate from Table. �� �,y o.2+ s.� <br /> 120 <br /> 0.45 gallons per day per square foot of rock area. <»� �a� ��� �� <br /> 3. Calculate the absorprion width ratio by dividing the rock layer loading rate of 1.2 <br /> gpd/ft2 by allowable soil loading rate: <br /> 1.2/0.45 =2.67 <br /> 4. Multiply the absorption width ratio by the rock layer width to determine the <br /> required absorption width; <br /> 2.67 x 10 =27 feet <br />
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