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PRESSURE DISTRIBUTI41� SYSTENI <br /> ��,>u�r�� <br /> . . . .:.. • <br /> A/7 b�ced rectarrgles must be enterod,the rvsf wia be cotculaieci. ..•,.�� °tl°°'� ' �• <br /> , , � 'oo-:r.�'r�.�h. .- <br /> 1'^��'°P.v+�l.i�«'�.. <br /> 1. Sefect number of pertorated iaterals: � <br /> 2. Select petfo+'ation spacing= �ft E�:Mds(rrMlaCiA�{vtthtlard2/A#�cllparfoR7lfdlt <br /> v.r sca�or Ao q,aro,►�amc d�Fw�pv�onanon <br /> 3_ Since perForations should not b�pfaced doseP that 1 �oot to v�roson <br /> tF�e edge of ttte rock layer(see diagram},subEract 2 f�eet frnm � � sn <br /> the rodc la r le th <br /> 63 -2 ft= 61 ft �s e ia �a 2e <br /> 3A 8 73 i7 � <br /> rock layerlerrgth � ss > >2 ia �s <br /> d� 7 11 16 23 <br /> 5.D 6 1V 1Q 2� <br /> � Determine#he rxm�ber of spacas between perforatiorrs. <br /> Divide ft�e length(3)6y per�oratlon spaar�q(2)arxi nound dawn to nearest whofe number. <br /> Perforation spacing� 61 �ft I 3 R= 20 spaces <br /> 5. Number af perfaretions is equal t�one pius the number of pe�i'oraHon spaces{4). <br /> "Check frgur�E-4 to assure the number of perforafiorrs per latsra!guarante�s <br /> <Zo90 dlscharge variatlan, <br /> 20 spaces* 1 = 21 perForationsllateral <br /> 6. A Tota1 number of perforations�perf�orationa per lateral(5)tane.s number af laterals(1). <br /> 21 perfs/lat x 3 laterafs= 63 perFprations <br /> ��: �q��o+'ae[n p�xn <br /> B. Calculate the aqu�re footage per perForation_ � <br /> Should be�1 Q sqft/perf. Qoes not apply fo et-grades. perfotattk5it c�idir�t�r <br /> 1. Rock bed area=rock widti� ft x rodc nead Ir�cnas <br /> � ) ��h(�) �r�,�j 8 3/t 6 ?js2 i!d <br /> 10 ft x 63 ft= 630 f� �.od o.i s vA2 o.sa o_�� <br /> 2. Squ2re foc�t per perforation z Rock gAd Area/rwmE?ef af petfs(8j <br /> 630.0 fl� / 63 perPs = 10.0 ftz/perf 2.�� a�6 0.59 v.s0 1,�t <br /> �.o aa� aea ��a �.� <br /> 7. DAt8rT1't�le r�quit+ed flOW f`afi9 by tnuftiPlyinB the tofal nW�nbet �use i.o rc�c,t,c��n,y��xn�L�r,c,rr,�s. <br /> Of perforatlonS(8�A)by flC7w per erforation,s(s��gLke E-6) �� �.o r t �x r. ,a. <br /> 63 perfs x 0.56�9Pm�Perfs= 36.3 gpm <br /> 8. If laberals are connectsd ta header pipe as shawn f ��s�_.;a,,.W <br /> in �iguFe E-1,to selecf m'uiimum requfr6d Iate1�E i - ``"`•""""""' <br /> ��:�'''" ' <br /> ,xF�r,-�'" �.��=�_=�1.= :.�y� <br /> di�meter,enfer f�qure E-4 Mritft perForation spaciR�(2)and ,�„s.---' �,- . <br /> number of perfvratiar►s perlaterai(5). _�.,.�..T=�=�''' ' <br /> ". <br /> r�� a`�wr's;s�,w��o <br /> AG��61�YonRoid tOoaf�tl nr eere a►a�ryry�.rn <br /> 5�Ilec.�minimum diameter for perforatec!taterals= 2.p lnches . <br /> 9. If perforatecf fateral sys�n is aitached to manifold pipe ,��,,,�,�.�, _.a.,�.;:�. <br /> near tt�e cer�ar, fike Figure E 2, perforated letet�l length(3} m pnwderayv�ni <.:�=- <br /> j=��� �r�7 <br /> and number of perforations per lateral(5)will6e appro�amately �y�-=�f>�"Y'•"'���v��'r'-%'" <br /> F_�. _�J-�� <br /> one half of tt-�at in 9tep 8. Using these values,select .:=`?^_ �-=���a sl=`.`� <br /> minimum diamstet'for p�rfar�ted lateral= �i�hes. �"—��:_� _�___=�=���� <br /> ��� <br /> �.y-�� �iw n�.cwy <br /> I hereby certify I have oomp�efed this work i�ftccordanee with a!I applicable ordinanc�s, rules and Iaws. <br /> � (sigrrahire} �p {f�se#� G `7_/^a Z (date) <br /> 5t 3`�dd SZ85-586-ZZ9 FZ=G1Z rRA7./FR/!R <br />