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- IVlaund Design VUorksheet �Forflvws up to 'i200 gpd) <br /> A!!boxed�edangfes mvst be entered,the r�st wilf be calculated_ — <br /> A. FLOW prl:61�rnot�d Sewage�wss fn 6dasPet fb� <br /> �stimated 750 gpd(se�ilgu�A-1} � <br /> or measured x 1.5(safety factor}= g�d �� �s� �� �d� �ry <br /> 2 300 D� 160 60% <br /> $. S�PTIC TANK L[QUIQ VOLUIUtES s �Q 300 2i� ofihe <br /> Septic tank capaGty 3 440 galions(see frgure Gt) 4 �� � �' y� <br /> 5 �5d d50 296 �ihe <br /> C. SdILS(5lfe evaluat�n dats) b �00 525 332 Cla�l, <br /> 1. Depth to t�shidfig iayer= �.5 � f 1060 � 37J 0.ar 11 <br /> 2. Depth of pet�da�on tests= 12 frtches 8 12�€1 675 d09 cdurms. <br /> 3. Texture loam <br /> b_ Sal foading rate(see Flgure D�3 0.5 gpd(f#� <br /> Percolation ra#e 4o MPl <br /> 5. %Land Sfop@ 3 % p.3�: �us:orpharr w,�ct.st�eq�T.we <br /> PWooi.n�iw� La.em�R�w <br /> �-1: Se ic T�nk C e�ftha in uE{unsl ���r� soa�r�.Q c�uao� w�«r««� <br /> P��+Y' R�aa <br /> Nurn6er'o� �iltm�m�n Iaquicf l.igu�d c�apa,ci�•�rith �4�d�D�b' aQ��n� M�� Y,z� t.oa <br /> � tY ��� with di��c <br /> 8�rktc�rnns d Iift i�ida _ . �"°'°°'�� <br /> 2 or]esa 750 2123 1� �w °o,so °U <br /> 3nrd 100f1 iS00 <br /> 5�r 6 LSO6 �Sp � 4a xo 6a ' r�.y`.,, o�ss 2cr <br /> '',S or 4 24�{} 3QQ0 <br /> 3t)QO �i a c.�„ <br /> dl io 13 6p� 02! 5.00 <br /> E�Ss <br /> owrr a,ai 7 2 • - <br /> 'S�+n.�dnden�d far urN�o3a rai 6�a�t x n�ram�ro <br /> D. ROCK LAY�K aIMEtVSIONS <br /> 1. Multiply average design flaw(A)by 4.83 fo obtaln required area af tock layer: Item A z 0_83= <br /> 750 gpd x 0.83 ft�gpd= 672.5 ftZ <br /> 2. Determine rcack layer width =0_83 ft2/gpd x�inear Loadirtg Rate(LLRj(see LLFi chart) <br /> 0.83 ft�lgpd X 12 = 9U,4 ft <br /> LLR Chart <br /> Perk Rafe LLR <br /> <120 MPI r_12 <br /> >=120 MPI <=6 <br /> 3_ Le�gth of nxk layer=area divided by width= <br /> 622.5 ftz 1 1fl feet= 62.5 feet Use 63 it <br /> E. ROGK VOLUME <br /> ?. Muftiply roc�c ar�ea by rock depth to get cubic feet of t�dc <br /> 622.5 X 9 it= 622.5 fts <br /> 2 Divide ft by 27 ft�lydg to get cubiC yards <br /> 622.5 fC� / 27 = 23.'! yds <br /> 3. Multlpfy cubic yards by 1,4 ta get vvelght o�rodc in tons; <br /> 23_1 yd3 X 1.4 iontyd� = 32.3 tons lJae 34 Torts <br /> F. A�SOaP710N WIDTH <br /> 1. Absorption width equals absorption r�tio(see F{gure D-33}times rvck layer width <br /> eZ ��dd 8Z85-986—ZZ9 �i�ei E00Z/69/�E <br />