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1997-00943 - new septic system
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2995 Deer Run Trail - 04-117-23-23-0033
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1997-00943 - new septic system
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Last modified
8/22/2023 5:10:36 PM
Creation date
6/20/2016 11:44:05 AM
Metadata
Fields
Template:
x Address Old
House Number
2995
Street Name
Deer Run
Street Type
Trail
Address
2995 Deer Run Tr
Document Type
Septic
PIN
0411723230033
Supplemental fields
ProcessedPID
Updated
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' ' MOUND DESIGN WORKSHEET 5 <br /> (For Flows up to 1200 gpd) <br /> A. FLOW Estimated Sewage Flows in Gallons per day <br /> Estimated � gpd Number T�� Type D) Type ID T� <br /> or measured - x 1.5 = - gpd. °` <br /> 2 soo Zu �so � <br /> B. SEPTIC TANK LIQUID VOLUMES a 6 0 �s° i's86 °f"� <br /> ��� <br /> /Z.�b�--/lyDd gallons 6 '90�o su 3sz T�1. <br /> 7 1050 600 370 ll� <br /> 8 1200 675 408 � <br /> C. SOILS (refer to site evaluation) , ,� `°'""v'S <br /> Sc tic iank Ca aoti s(in allum <br /> 1. Depth to restricting layer= . /O inches feet �q�d�,���Y <br /> 2. Depth of percolation tests - /� inches "°^����� MinimumLiyuid liyuidcaraarywiN ���,,�& <br /> Bednn�mt Gpacity gubage dispcual lih i¢side <br /> 2�x less 750 1125 I500 <br /> 3. Texture �A� Percolation rate�-•s=a'r�mpi �,.<< �� ,� � <br /> 5 ar 6 1500 2250 3000 <br /> 4. Land slope � % 7,R ur 9 2� ,� � <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 = <br /> �sv gpd x 0.83 sq. ft./gpd = 2 z sq. ft. <br /> 2. Select width of rock layer (max 10' if<120 mpi max 5') _ %4 ft. <br /> 3. Len�th of rock layer = area=width = � a=6ne.o sa o-o;n.eo aea=a Qo > <br /> 900 00o Dp' <br /> `�i � sq. ft. - /O ft. _ lcE3 ft. :�°a ��°�<°(((""��� a <br /> �. �-0 <br /> -� 4AOp�Od QQ'oenb�eoO o p <br /> �o do Ro oonD ffD ab:�:. <br /> Width�ft �p�000 o'p0'�OQDD D a oD e <br /> <120mpi <10' Length��ft <br /> E. ROCK VOLUME <br /> >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock;�sq. ft. x �� <br /> ft. _�cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> �L�' cu. ft. =27 =��cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; �� cu. yd. x 1.4 <br /> ton/cu. yd. _�tons. <br /> F. ABSORPTTON WIDTH Absorption Width Sizing Table <br /> 1. Percolation rate in top 12 inches of soil is���'mpi ������, c�„� �o��� <br /> Mioutts pa Inc6 Sal Texturc per day per width to Rock <br /> Texture �-✓`^' (MPI) squazc foot Layer Width <br /> Fazter than 0.1 Coarse Sand I.20 1.00 <br /> 0.1 to 5 Sand 1.20 1.00 <br /> 2. Select allowable soil loading rate from table; o.��o s Fine Sand o.�o z.00 <br /> �Q a 6�a s o.� , <br /> , �d�ftz �b�0 3 '��, � �'� <br /> to 45 t'Loam 50 -2�.40 <br /> 46 to 60 Clay Loam 0.45 2.67 <br /> 60 to 120 Clay 0.24 5.00 <br /> 3. Calculate adsorption width ratio by dividing rock layer s�oW«�,��zo c�ay o.zo e.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loadin rate; <br /> 1.20 gpd/ft2=�gpd/ft2= � � v v <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> � x�_ft - 2C•r ft <br />
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