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F-17
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<br /> F
<br /> ' PLJMP SELF,�ON p�ZOCEDURE
<br /> f10 PERfOitAT10N CF 4 PERfORATEp LdTERAL
<br /> A. Determine pump capacity: �...�..,
<br /> Gravity Distribution T.,,�,
<br /> 1. Minimum suggested is 600 gallons per hour(l0 gpm) to stay ahead of - M w��w �,K�d,�„
<br /> �'wq s..�.�er. �:�ie...�ro,. �,..�.....a
<br /> water use rate. ,..,...,,�,.,,
<br /> 2. Maximum suggested for delivery to a drop box of a home system is 2,700 ., . %-���^a���� �,��^��",
<br /> .,�� ,..e, ,00
<br /> gallons per hour(45 gpm)ro prevent build-up of pressure in drop box. , ,,;,,,„ -., ,.,., ,Z•„ ,,,,
<br /> H ol Ra�Lq«
<br /> � PY1v'�Ilrv Vt�IM a�
<br /> Pressure D'utibution c�..�s.,.�.,. ��'�^" ��•^�
<br /> 3. a. Select number of perforated laterals �
<br /> o.+..�s.0 .,...,., s�,iw
<br /> b. Select perfontion spadng=�_feet �,,,,,.,.,��,,,�,,,,
<br /> c. Subtract 2 ft from the rock layer length.
<br /> ��-2 ft. _��feet
<br /> d. Det�rrrune the number of spaces between perforations.
<br /> Length perf.spacing=,�f t. +�ft._� spaces tt�q„i�d Perforaeon Disch e
<br /> e. ,�spaces+ 1 =_1�perforations/lateral u,g�llons per a,i„��e(gp�
<br /> f. Multiply perforabons per lateral by number of laterals to D��'Be , �a ,
<br /> get rotal number of perforations. W�� x p!� �Q,,_�perforations. H�d �� � ' `�'�°"'
<br /> g• � X�_�$Pm.
<br /> 1.Oa 0.56 0.74
<br /> SELECI"ED PUMP CAPACITY �� � gpm 2.�b Q.gQ 1.04
<br /> B. Determine head requirements: a. Use for single family homes
<br /> 1. Elevation difference between pump and point of discharge. b. Use for all other applications
<br /> �� feet
<br /> � 2. If pumping to a pressure distribudon system, five feet for pressure
<br /> required at manifold if gravity s stem,zero.
<br /> � feet
<br /> 3. Friction loss
<br /> a. Enter friction loss table with gpm and pipe diameter. Pipe La,gch
<br /> Read friction loss in feet per 100 feet from table. � Poin�of Dischugc
<br /> F.i.. _�_ft./100 ft of pipe �i�;
<br /> b. Determine total pipe length from pump to discharge F_Icvadon Difference�
<br /> poinL Add 25 percent to pipe length for fitting �
<br /> loss,or use a fitting loss chart. Equivalent pipe p ���°'
<br /> length- 1.25 times pipe length= F-18b
<br /> 3� x 1.25 =�_f ee t
<br /> c. Calcul.ate total friction loss b multi 1 n 1.5 inch 2.0 inch 3.0 incn
<br /> Y P N g �n Ftiaim lm pa 100 ft o(pipe
<br /> friction loss in h/100 h by equivalent pipe length. �
<br /> 10 0.69 0.20
<br /> Total friceon loss= �-b� x 3 tS +100=�_feet 12 0.96 0.28
<br /> 4. Total head required is the sum of elevation difference, 14 1.28 0.38
<br /> special head requirements,and total fricdon loss. 16 1.63 0.48
<br /> 18 2.03 0.60
<br /> 20 2.47 0.73 0.11
<br /> _�+ � +�_ 7S 3.7 3 1.11 0.16
<br /> (1) (2) (3c) 30 5.23 1.55 0.23
<br /> 35 7.90 2.06 0.30
<br /> 40 11.07 2.64 0.39
<br /> TOTAL HEAD �_feet 45 1a.73 3.28 O.a8
<br /> 50 3.99 0.58
<br /> 55 4.76 0.70
<br /> C. Pump selection 6o s.bo o.sz
<br /> � 1. A pump must be selected to deliver at least
<br /> ._ �_gpm (Step A) with at least �^ feet of total head (Step B).
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