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i�-17 <br /> ��p SELECTION PROCEDL�E <br /> EI�D PERFOqAT10N OF p pERFp{7ATF() L4TERAL <br /> A. Determine pump capacity: ,_�,,,,�,,,,, <br /> Gravity Distribution ��T�� -` <br /> 1. Minimum suggested is 600 gallons per hour(]0 gpm)to stay ahead of , � •, -� d��„w�k�� � <br /> water use rate. • ��°� •��-���_•�•a� <br /> .�,...a.e."�,.,, <br /> 2. Maximum suggested for delivery to a drop box of a home system is 2,700 . �+«���a��»a��_«�����+ <br /> - � Mro cov rwo. too <br /> gallons per hour(45 gpm)to prevent build-up of pmssure in drop box. ,•.,.R,„ -u�.,�, ,Z•,o E,a, <br /> IE o!Rxk Lqer <br /> Pressure Distibution �•P'"�«�u�id" <br /> cw.�saw inx <br /> 3.a. Select number of perforated laterals <br /> b. Select perforation spacing= feet ��••���� •,.�•�„� <br /> BNen PbtlnO Sand lnrr <br /> c. Subtract 2 R from the rock layer length. <br /> -2 ft.= feet <br /> d. Det rrrune the number of spaces between perforations. <br /> �Iigtti �PSf.Sp3C111g= ft.+ ft.= spaces Reyuued Perforahon Disch�'ge <br /> e. spaces+ 1 = perforations/lateral u�g�uons per a,u,�ee cgpn) <br /> f. Multiply perforations per lateral by number oE laterals to ����e , <br /> gettotalnumberofperforations. ,,�,�� x�_�= perforations. H�� �2m��'' �md�'' <br /> g- �r X��= gP�- <br /> 1.Oa 0.56 0.74 <br /> SELECTED PUMP CAPACTTY��7 gpn, 2.0�j Q.$� 1.04 <br /> B.Determine head requirements: a. Use for single family homes <br /> 1. Elevarion difference between pump and point of discharge. b.Use for all other applications <br /> �_feet <br /> 2. If pumping to a pressure distribudon system,five feet for pressure <br /> required at manifoid if gravity system,zero. <br /> .S feet <br /> 3. Friction loss <br /> a. Enter friction loss table with gpm and pipe diameter. P�pe Lengch <br /> Read friction loss in feet per 100 feet from table. � Poinc of Discharge <br /> F.L._�f�/100 ft of pipe <br /> b. Determine total pipe length from pump to discharge Elevauon Differencel <br /> point Add 25 percent to pipe length for fitting �P <br /> loss,or use a fitting loss chart. Equivalent pipe <br /> length-1.25 times pipe length= F-18b <br /> x 1.25 = feet <br /> c. Calculate total friction loss b multi 1 n 1.5 inch 2.0 inch 3.0 inch <br /> Y P Yl g g� Pr�aim locs pc 100 fl ot pipc <br /> friction loss in ft/100 ft by equivalent pipe length. 10 0.69 0.20 <br /> Total friction loss= x +100= feet 12 0.96 0.28 <br /> 4. Total head required is the sum of elevation difference, 14 128 0.38 <br /> speciai head requirements,and total friction loss. 16 1.63 0.48 <br /> 18 2.03 0.60 <br /> (/ + �/� + �� 20 2_47 0.73 O.l 1 <br /> - 25 3.73 1.11 0.16 <br /> (1) (2? (3c) 30 5.23 1.55 0.2: <br /> 35 7_� 2.06 � 030 <br /> 40 11.07 264 0.39 <br /> TOTAL HFAD feet 45 14.73 3.2R 0.48 <br /> 50 3_99 � 0.5f <br /> C PUmp selection bo s.�� o.sz � <br /> I <br /> � 1. A pump must be selected to deli��er at least <br /> � �_gpm (Step A) �>ith at least �3 _ feet of total l�ead (St�>� 8}. <br /> 1- <br />