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1999-011566 - new septic
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140 Crystal Creek Road - 33-118-23-33-0010
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1999-011566 - new septic
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Entry Properties
Last modified
8/22/2023 4:50:13 PM
Creation date
6/6/2016 2:11:18 PM
Metadata
Fields
Template:
x Address Old
House Number
140
Street Name
Crystal Creek
Street Type
Road
Address
140 Crystal Creek Road
Document Type
Septic
PIN
3311823330010
Supplemental fields
ProcessedPID
Updated
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, , , MOUNi) I�ESI(:N Wt)KktiHi�I:"T <br /> � , (F�,r� I�l���v� i�J, t�� 1?(1(I }��,�11 <br /> —----- —---- <br /> n Fl ( )1�� _ _ _ -- -- _ - --_ <br /> �---- �-----. ...--I�ninaird tirwap�I�lows in(�all��m i i <br /> fN fa� <br /> "� I�K1) <br /> f',titllll7�l'lj ��_� ���U ��Numbn IT17vl Typt1l�T�rlll <br /> 9 i���r <br /> ��r mF�asured �- ---- x 1.; _ - f�F�� 'Es�;x.,ri � i�- <br /> � <br /> _ _- - ___ <br /> l : _1 �x� zz, �x�, - _ <br /> t3 �F.PTI(� �TANk Ll(.��UII� VOLUME� ; � �; ;`x' ;�� o� <br /> 3�� ������ _ ��311c)ri5 � `� � 7x� ax� �ty . ��"�' <br /> �, � 4(KI S2S ( 13? � I>�x� <br /> , � 1050 � (�(kl � 170 �, 11.. <br /> r I100 � 67S � J(k{ � iII <br /> �. �C)1L5 (refer to s�te evaluat�c�n) � ' i �����, <br /> �-------- <br /> .� tic Tadc C wt.a/u W.,n.i <br /> 1. Depth to restrictin� layer = �� __ inches _1_�, 6�_fec�t ��wa��„�„� <br /> 2. Depth of ercolation tests = I Z jnC]�E�S """"""' "'°"'""°�'°uid �"''"di'"�ry"`" `"'^a:�•�,we, <br /> NMn..m� C:�aa�Y Ru�Fc Ai�IKnal i�h inc�dr <br /> 3. Texture �� �'-r� Percolation ratc� h�� '�•�' 'So "2' ,�, <br /> 1__,�—__ mp� ��.,. �� �� ,� <br /> 4. Land slope __�-,�__°/ �•"" "°° '='° '°°o <br /> o �x.,,v �au �aoo xqo <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 = <br /> � gpd x 0.83 sq. ft./g-pd _ �:�q. � <br /> 2. Select width of rock layer (max 10' if <120 mpi max 5') _ _ ITI _ ft. <br /> 3_ Le��of rock layer = area - width = o p� �. ��qe�� , �6�,�.=�.,oe �� <Q <br /> - - — �q' �' �— �. �J� _ f t. �^��o�xD�`.D ooQ d° a. �ir—c--�-ot'�T—y.'`� <br /> �GOo`�e���oocoriP n� xD �� <br /> wlduj �/ ) fr a �o� odD'bO�OD D ep ` <br /> "__L=_ <br /> <120mpi <10' Length�_ft� <br /> E_ ROCK VOLUME >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock;�sq. ft. � <br /> ft. _�cu. ft. � . <br /> 2. Divide cu. ft. by 27 cu_ ft./cu. yd. to get c�ub� yards; <br /> �cu. ft. = 27 = /�_3 cu. yd- <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; cu. yd. x 1.4 <br /> ton/cu. yd. _� tons. <br /> F_ ABSORPTION WIDTH Absorption�dth Sizing Table <br /> 1. Percolation rate � top 12 inches of soil is y� -�m � <br /> p a�d��rc��� c�,� amaornb�a, <br /> Textur ' Minu�u per loc6 Sal Tcznuc per day pv widW to Rxk <br /> (MPI) iquarr foot Lay«W�dtti <br /> Fis¢r than 0.I Coarsc Ssnd 1.?0 �_pp <br /> 2- Select allowable soil loading rate from table; o�«� Fx's�,a obo �o <br /> �_"� d/ft� a�o�, s�Y�„ 0,9 � s� <br /> ,� �e�0 3a � o ao z o0 <br /> 31 io 45 Sih Loam O.SO �.ap <br /> 46�0 60 Clay Lwm ,O 4 S. �_ <br /> 3- Calculate adsnrption width ratio by dividin� r<�ck la��er 6°'°'zo a�� oza soo <br /> sio�m�,i zo ci�y o zo b o0 <br /> 1<�ading rate of 12U gpd/ft2 by allowable soil loadin�; rate; <br /> 1.20 g�d/ft�= _-- gF'd/ft� _ ���-- <br /> � a '�lultiE�l� .�ij���tE�t���n �,�i�lti� rai��� i��� iu� 1� 1.��'rr t�.-icit�� t�, y,��t <br /> rc��tnred ad�ur��i�c�n �����3th. <br /> ,��_7 � _/C%_ �t ���� r, <br /> --- - <br /> _- - <br /> - - - <br /> -- ----------- <br /> _ __ _- --,----- _- � <br />
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