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1998-009920 - new septic
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Crystal Creek Road
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75 Crystal Creek Road - 33-118-23-33-0003
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1998-009920 - new septic
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Entry Properties
Last modified
8/22/2023 4:49:53 PM
Creation date
6/6/2016 12:27:59 PM
Metadata
Fields
Template:
x Address Old
House Number
75
Street Name
Crystal Creek
Street Type
Road
Address
75 Crystal Creek Road
Document Type
Septic
PIN
3311823330003
Supplemental fields
ProcessedPID
Updated
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1', ��. �? " . �, ,.� ��1-'�'3 ' . <br /> - ' �L1`���"��- _ � 1 ���_ s-�'�� - y'_ � <� <br /> � , , <br /> G. DOWNSLOPE I��WIDTH s� � a - a. -� <br /> 1. If landslope is�6 �more,subtrar..t:ock layer width from �-��S - � �- � , <br /> adsorption width to obtain minimum downslope dike toe S-�� � _ y -o <br /> ��.'� ft- �� ft =�2_feet <br /> 2. Calculate Minimuul�mound size base:� ��n geometery: <br /> a. Determine c;tpth of dean sand fill at upslope edge of rock <br /> layer: Separation _ ,l o N feet ----�-, - ____. <br /> b. Multiply rock layer width by landslope � +oot'co�.� <br /> to determine drop in elevation; : rooc� o ;e <br /> Slope Di�B1'B12CB S�peretlon te�t ►�S� �,� ` �'S <br /> / fu� Slop� 0 fieren�e fa,�t <br /> /O r.�_%y 100 = .�feet UDslope W10t� , <br /> c. Add de pth of clean sand for se paration (2a) -L--feet R o c k B e G W 1 G t� �°' �� <br /> �J� teet DownsloDe Wfat <br /> at upslope edge,depth of rock layer (1 foot) to depth of a�� <br /> cover (1 foot) to find the mound height at the upslope edge � �'°e1 `-� <br /> -��w�F=. <br /> of rock layer; -� <br /> .c� ft+ lft + lft= �.� fee► <br /> d. Enter table with landslope and upslope dike ratio. <br /> Select dike multiplier of � .3"�� <br /> e. Multiply dike multiplier by upslope mound height <br /> to find upslope dike width: ,�3 x 3"o = 1c� feet <br /> f. Add depth of dean sand for slope difference (2b) at <br /> dov,�islope edge, to the mound height at the upslope edge <br /> of rock layer (2c) to fir..d the downslope height; � <br /> 3,� ft+�_ft == � •� feet + ,S � .�� - �t •�� <br /> g. Enter table with landsloge and downslope dike ratio. <br /> Select dike mulripliex of__�� �� <br /> h. Multiply dike mul�plier by downslope mound height <br /> to get downslope dike width: S.o x �,S -� �-�feet <br /> i. Compare the values of step G.1 and S�ep G.2h Select the <br /> greater cf the two values as the downslope dike width; S y � <br /> a�, feet ;; >, , _ <br /> <: <br /> uosioo�M�atn <br /> j. T�tal mound width is the sum of �-�••l <br /> . <br /> upsloge ciike (G.2e) width plus rock ' ' P ' <br /> . k CK C�C WIOtn ': i <br /> � � �a �i��t :., <br /> layer width (D.2; plus e �os�oo.W�a�� �os�ooe w�a�� <br /> downslope dike width(G.2i 3 -L� ���1 ��leet <br /> ): y � ! ��J ; ; <br /> lo_ + _/� t-�ft+�_ft + �_ ft = _�3_ feet � , � ; �� ���.i..�. <br /> k. Tota?mound lengttt is the sum of �3 � 1� Downsiope W at� ; <br /> �E <br /> upslope dike width (G.2e) plus rc•:k layer i <br /> len h D.3 lus u slo e dike width (G.2e); �� � <br /> St ( ?P P P <br /> �ft+��ft + �_ft = ,j�. feet <br /> a:� -+� 3 � �- a� _ �S o �� . <br /> TotelL�nptn <br /> own ope ps ope <br /> 3:1 �:1 5:1 &1 7:1 3:1 6:1 5:1 &S 7:1 8:1 <br /> 7L aiope <br /> 0 3A l0 5.0 6.0 7.0 3.0 4.0 5.0 60 7.0 8A <br /> I 3.09 �.17 5.26 638 753 2.91 3.85 4.76 5.66 65/ 7.11 <br /> 2 3.19 l35 556 �82 8•i� 2.83 3.7D 45� 536 61� 6.90 <br /> 3 330 l54 5.88 732 8.86 275 357 435 5.08 5.79 bA5 <br /> 4 3�t1 476 b25 7.89 9.T2 268 3.15 �.17 t81 5.16 6A6 <br /> 5 ;53 S.OD 667 857 10T1 2.61 �.333 d.QD 4b? 5.19 5.71 <br /> 6 3.66 5.?b 7.1� 938 1207 254 3.13 3.85 l41 1.93 S.t1 <br /> 7 3�p 556 7.b9 1034 1373 2d8 3.12 3.iJ 113 �.70 5.13 <br /> 8 3.% 5.88 833 115� 1591 262 3.03 357 LQS 4.iS 4.88 <br /> 9 4.11 675 9.09 13.O1 io.92 236 29d 3.45 3.90 �30 4.G5 <br /> 10 «9 6.67 10.0 15.00 2333 231 286 333 3.75 1.12 4A4 <br /> 11 4A6 7.14 il.11 17.65 30.�3 2.2b 278 32! 3.61 3.95 t.:.6 <br /> lZ ��.f, 7.69 1250 21.43 4375 221 270 3.12 3.�9 3.80 4.08 <br />
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