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MOUND DESIGN WORKSHEEI' <br /> ' � (For Flows up to 1200 gpd) <br /> � A. �.ow �����,�.�N�,�.��„�,o.Y� <br /> Estimated�gpd N,:„e« ,�� .�,�it ry�u� �ry�rv <br /> or measured=x 1.5 = -- gpd. �� <br /> z aoo xu �eo .o• <br /> a 4so �o� z�e .� <br /> B. SEPTIC TANK I.IQLJID VOLUMFS � s � ;� � '� <br /> I-,�.,.��0 � 1 bao gallons i �� � i�o �,.�,. <br /> •M <br /> e 1200 67S 406 <br /> C. SOILS (refer to site evaluation) r,�eQ ,,�,,,,,, ��, <br /> 1. Depth to restricting layer= 3y`�� a.�," inches "r �."• <br /> s� � � <br /> 2. Depth of percolation tests = �_inches `~" <br /> 3. Percoladon rate C .�L__mpi 2i��` i,o i'.s'o�o <br /> 4. Land slope { % �R� � � <br /> ov�9 5+�1SM C-6 (a 13) <br /> D. ROCK LAYER DIIv�NSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer:A x 0.83 s <br /> ��v . gpdx 0.83 sq. ft./gpd = �sq. ft.-}-���=�y� <br /> 2 Select width of rock layer(10 feet or less) = i o ft. <br /> 3. Length of rock layer � area+width= Rock Bed <br /> �sq. ft. + �ft. =�ft. ,., , ; ��. .,;*,, , <br /> ,•� �.s ���'���;}�,'.wt���� <br /> � ti �•,., . . . <br /> .�.�•i�•i•i �•r��r• � •r•i• <br /> ti.ti.�.{�ti.��.�.{.����.�.ti �dth 510 ft. <br /> r.r•r•�•S r•f r•��r•�•r•r•r• <br /> �.ti•�•�•ti ti-�ti•ti•L•ti•�•ti•ti��•..� <br /> .�.i.r•�•r•�•�•r•r•�•�.�•r•r�•r• <br /> E. ROCK VOLUME �— �'�' —� <br /> 1. Multiply rock azea by rock depth to get cubic feet of rock; <br /> (e�s y sq.ft. x�ft =�cu. f t. <br /> 2. Divide cu. ft.by 27 cu. ft:/cu. yd. to get cubic yards; <br /> �cu,ft. +27 a,..�_cu. yd. <br /> 3. Multiply.cutiic yards by 1.4 to get weight of rock in tons; <br /> �cu.yd.x 1.4 ton/cu. yd. _� tons. <br /> F. A�QR��NT��•� [— �•�A'W1 ae�WldtASlri�+ Lbk <br /> YY1L <br /> GOw AwV� <br /> 1. Percolation rate in top 12 inches of soil is L_q mpi M���� �ilTexture ,:.� «,': <br /> c�,� �.. .:�., <br /> 2. Select allowable soil loading rate from table; F�:c�c��,o.i oarse Sand 1.2o i.00 <br /> i 0.1 to 5 Sa�nd 120 1.00 <br /> c�i_ SPd/f� o.i co s Flne Sand� o•�o z.00 <br /> 6 to 15 ndy Loam 0.79 152 <br /> 3. Calculate adso tion width ratio b dividin rock la er tb co ao �oam o•� Z•� <br /> 2p y $ }r 31 to 45 Silt Loam OSO 2.40 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; 61 c�o� 21 0 �'�a�y"a' ola s o0 <br /> 1.20 gpd/ft2f .� gpd/ft�_ ��(o� Slower than 120 Cla - - <br /> "Sof11uv4ns 501�or mon d Rne or va�Rne�u,d <br /> 4. Multiply adsorption width rario by rock layer width to get <br /> required adsorption width; <br /> �,s�,X_�_ft= ��� ft <br />