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1998-010753 - new septic
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35 Crystal Creek Road - 33-118-23-33-0002
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1998-010753 - new septic
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Entry Properties
Last modified
8/22/2023 4:49:50 PM
Creation date
6/2/2016 2:25:18 PM
Metadata
Fields
Template:
x Address Old
House Number
35
Street Name
Crystal Creek
Street Type
Road
Address
35 Crystal Creek Road
Document Type
Septic
PIN
3311823330002
Supplemental fields
ProcessedPID
Updated
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' � MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. �.OW Estirnued Sew�6e Flow�cf Callo�s pa Day(gpQ) - <br /> Estimated �oc� gpd <br /> Nianber <br /> or measured - x 1.5 = -- gpd. B�°�n„ �'p`I ��i TYP�III �y�rv <br /> s soo z2s �so �o. <br /> 3 450 300 218 't <br /> B. SEPTTC TAI�TK LIQUID VOLUMES ' 6°° 3�s zs� •� <br /> S 750 450 29� � <br /> /ODU g OI1S <br /> 6 900 525 332 � <br /> ' 7 1050 600 370 �� <br /> $ 12D0 675 408 <br /> C. SOILS (refer to site evaluation) <br /> , N�� ,�� �.Y, <br /> 1. Depth to restricting layer= a.�t" � a�' inches ��, �,�,, �, <br /> 2. Depth of percolation tests = i a''- �6�" inches `'+'"' `'""' <br /> 3. Percolation rate y •y mpi 2;a`4` ,'o�oo i',s o <br /> 4. Land slope 5' °10 �Q a zo�0°o0 � <br /> wv 9 See fis.C-6 (i IS) <br /> D. ROCK LA,YER DIIv1INSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer:A x 0.83 = <br /> o� . gpd x 0.83 sq. ft./gpd = L sq. ft.-��o�» = s����, <br /> 2. Select width of rock layer (10 feet or less) = i� ft. <br /> 3. Length of rock layer = azea y width = R� g� <br /> 5%�sq. ft.+ ��ft. _��ft. �...,.,...,.�...,...,.�.,.�.,.,., <br /> I•1.1•1•1•1•r•1•t I•t•t•!•t•t•t• <br /> {•1•ti•ti•1•ti•ti•'►•ti•ti•ti•ti•ti•t•ti•ti•ti <br /> �r•r•r•r•r.�.r•r•r r•i•r•r•r•r•r• �dth <_10ft. <br /> •�.�•ti.�•ti•ti-ti•ti.ti•�.ti•�•ti•ti•ti•ti <br /> �f ti�1�tif ti:1r1�ti�ti��fti�ti�tifti`1r��1 <br /> 'f'f•f'f'f'f'f•f'r'f•r'�'f'f'r'f• <br /> E. ROCK VOLUME � 1'�'�' -� <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; �� <br /> �sq.ft. x �.o s ft. =S�y cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> s�N cu.ft. y 27=��cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> �cu. yd. x 1.4 ton/cu. yd. _� tons. <br /> F. ADSORl'TION WIDTH G��`� L-D'� '� o„w�de�s�, Lble <br /> 1. Percolation rate in top 12 inches of soil is �•y mpi PetcoLtlmRaee G°� a�°°' <br /> t,aj„t,u,pr,;,,d, Soil Texture �� "d,6i° <br /> (mpil i.e .%.e.vea. <br /> 2. Select allowable soil loading rate from table; d� <br /> Faster than 0.1 oarse Sand 1.20 1.00 <br /> � 0.1 to 5 Sand 1.20 1.00 <br /> .u� gPd/ft� 0.1 to5 FneSand" 0.60 2.00 <br /> 6 to IS ndy Loam 0.79 1 a2 <br /> 3. Calculate adso tion width ratio b dividin rock la er 16 to�o �.,o�, o.bo z.�o <br /> � }� g }� 31 to 45 Silt Loam OSO 2.40 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; '�to bo cta �.oan, o.as 2.6� <br /> 1.20 gpd/ft2i ,u gpd/ft� = a.(�� S1owe�r,�n i2o Ciay o24 s.00 <br /> "Soil havic�509L or mae d Fux or vey finc sand <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> �. L2 x �o ft =�2 ft <br />
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