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MOUND DESIGN WORKSHEET <br /> • ' (For Flows up to 1200 gpd) <br /> A. FLOW Eitimued Sew�ge Flo�in Gallons pa DaY(gp� -- <br /> Estimated O � gpd N�� <br /> or measured - x 1.5 = gpd. a��� �`I �'p`u Tya ni ��rv <br /> z 30o zu �so � <br /> 3 450 300 218 °i <br /> B. SEPTTC TANK LIQIJID VOLUMES 4 �o0 3�s as� ,� <br /> 5 750 450 244 � <br /> � - /{�O C7 g�pj1S 6 900 525 332 "'° <br /> 7 IQSO 600 370 ,d� <br /> g 1200 675 408 <br /> C. SOIIS (refer to site evaluation) <br /> ,� ,, N�bc ��c c�.w. <br /> 1. Depth to restricting layer = �o a 3 o inches B� �, �,, <br /> 2. Depth of percolation tests = i�. - � � " inches `"""' `"°"' <br /> 3. Percolation nte � � � mpi 23 a`;` ,'o�oo ;•.s o <br /> 4. Land slope_S,� % �«a z o 3.�000° <br /> wa 9 See fis.C-6 (x 1S) <br /> D. ROCK LAYER DIIv�1SIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83 = <br /> n' <br /> ov . gpd x 0.83 sq. ft./gpd = �-1`�� sq. ft.-� ����� = s`+'% <br /> 2. Select width of rock layer (10 feet or less) = i�-� ft. <br /> 3. Length of rock layer = azea y width = R� g� <br /> S�� sq. ft. + �ft. = ss ft. �.�.,.,...,.,...�.�.,.,.,.,.,.,., <br /> ♦fti�ti�1��`\�1�1�1�tif�r�fti tifl�tifti <br /> tiftifti:ti:tifti:{:;f�:ti{ti:�rtirtif�f�rti �dth 510 ft. <br /> yf ti�1:�f ti�1�ti�tirlrti�l��f1f tiflrlrti <br /> •/•I•r•f•1•l•t•f•t•l.l.t•t•t•t•1• .. <br /> E. ROCK VOLUME �- I'�'g�' -�' <br /> 1. Multiply rock azea by rock depth to get cubic feet of rock; -� <br /> s�,sq.ft. x /•��ft. _�cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft:/cu. yd. to get cubic yards; <br /> S�� cu. ft. y 27=��cu. yd. <br /> 3. Multiply cubic yazds by 1.4 to get weight of rock in tons; <br /> �cu. yd. x 1.4 ton/cu. yd. _ �S tons. <br /> F. AD�'.�ORI'TION WIDTH �-�_q`1 L 0 q�� a„w�a�,s�, Lble <br /> 1. Percolation rate in top 12 inches of soil is �!. � mpi �Mo,,,�,R,� ��. R.�d <br /> M;,,L,u,pR,�,�t, Soil Texture �,� '"d,� <br /> (mpil �.. .e.o.ve <br /> 2. Select allowable soil loading rate from table; Faster than 0.] oarse Sand 1.2o i.00 <br /> � 0.1 to 5 Sand 1.20 1.00 <br /> '��, gPd�f� 0.1 to 5 fiine Sand� 0.60 2.00 <br /> 6 to 15 ndy Loam 0.79 1�2 <br /> 3. Calculate adso hon width ratio b dividin rock la er 16 co�o t oa�, o.bo 2.00 <br /> � Y g Y 31 to 45 Silt Loam OSO 2.40 <br /> load.ing rate of 1.20 gpd/ft2 by allowable soil loading rate; �co bo c�a [.o�, o.as z.b� <br /> 1.20 gpd/ft2�- ,k� gpd/ft� _ �• L'L_. Slowertha�120 CiaY o2a s.00 <br /> "Soil having SQ9L or morc d fux or vcy fine xnd <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> �x �v ft = a�.� ft <br />