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F-17
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<br /> ' PUMP SEI.ECTION PROCEDURE
<br /> ElD PERfORl�TIOH OF 4 PfRfOR4TEp I�TER4L
<br /> A. Determine pump capacity: W..�..,
<br /> Gravity Distribution
<br /> T�a«I
<br /> ]. Minimum suggested is 600 gallons per hour(10 gpm) to stay ahead of - . � a�„N�w�.k�d��,
<br /> 'w�r s.r�or. '�w...i ro,.u o.�o....e
<br /> water use rate. .,,�,,.,.,„,�,,,'
<br /> 2. Maximum suggested for delivery to a drop box of a home system is 2�7W MM�nen a��,b �.o,,,�,,,��,
<br /> ti»wo .ua, ,>o
<br /> gallons per hour(45 gpm)to prevent build-up of pressure in drop box. ,�.,;p,„ ; _y �,,., ,Z•„ :,,.
<br /> ie or n�� �«
<br /> Pressure Distibudon c�..,�,.,,,., ��"`���" `�
<br /> B.�ww M U��ni
<br /> 3. a. Select number of perforated laterals 3
<br /> � Pa $--3.- o�..�..i s.ii ►,...,.,s���»a
<br /> b. Select oration s cin feet �,,,,,,,,,,�5e,,,�,,,,
<br /> c. Subtract 2 ft from the rock layer length.
<br /> S S' _2 ft. _�_feet
<br /> d. Det��ine the number of spaces between perforations.
<br /> I.ength perf.spacing=�ft. +�_ft._�2 spaces Re9uued Perforation Disch e
<br /> e. �spaces+ 1 =�t�perforations/lateral ��o�P��U1e(Sp�
<br /> f. Multiply perforations per lateral by number of laterals to D�78e � .aP,, ,
<br /> get total number of perfoneons.�; x �tz 1e,,_ �I perforations. ��d 32 ' °�'��"
<br /> g' � " ��+=�gPm.
<br /> 1.Oa 0.56 0.74
<br /> SELECTED PUMP CAPACITY�_gpm 2,�b Q.8� 1.04
<br /> B. Determine head requirements: a. Use for single family homes
<br /> 1. Elevation difference between pump and point of discharge. b. Use for all other applications
<br /> �_Eeet
<br /> � 2. If pumping to a pressure distribution system,five feet for pressure
<br /> required at manifold if gravity s stem,zero.
<br /> � feet
<br /> 3. Fricdon]oss
<br /> a. Enter friction loss table with gpm and pipe diameter. Pipe Lrng�h
<br /> Read friction loss in feet per 100 feet from table. � Poinc o!Dischargc
<br /> F.i.. = a.�a�ft./100 ft of pipe � -� d
<br /> b. Deternune total pipe]ength from pump to discharge E]cva�on Diffcrence
<br /> pointi Add 25 percent to pipe length for fitting � �_, -•
<br /> loss,or use a fitting loss chart. Equivalent pipe p
<br /> length - 1.25 times pipe]ength= F-18b
<br /> 1'7 c� x 1.25 = ��_f ee t
<br /> c. Ca]culate total friction loss b multi 1 n 1.5 inch 2.0 inch 3.0 inch I
<br /> Y P Y� $ � ti,a;�,i�,�ioo n�r o��
<br /> friction loss in ft/100 h by equivalent pipe length.
<br /> Total friction loss= a.lo'� x �,)� +100=�_feet 10 0.69 0.20
<br /> 12 0.96 0.28
<br /> 4. Total head required is the sum of elevation difference, 14 1.28 0.38
<br /> special head requirements,and total friction loss. 16 1.63 0.48 '
<br /> 18 2.03 0.60
<br /> 20 2.47 0.73 0.11
<br /> `" + ,� + � 2S 3.73 l.11 0.16
<br /> (1) (2) (3c) 30 5.23 1.55 0.23
<br /> 35 7.90 2.06 0.30
<br /> TOTAL HEAD a (� feet 40 11.07 2.6a 0.39
<br /> 45 14.73 3.28 0.48
<br /> 50 3.99 0.58
<br /> 55 4.76 0.70
<br /> C. Pump selection 6o s.6o o.sz
<br /> I� 1. A pump must be selected to deliver at least
<br /> ,_, �� gpm (Step A) with at least � feet of total head (Step B).
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